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alexandr402 [8]
2 years ago
13

Calculate the heat (in J) required to raise the temperature of 3.02 g of solid silver from 22.3 degrees Celsius so solid silver

at 47.0 degrees Celsius?
Chemistry
1 answer:
Furkat [3]2 years ago
7 0

Answer: 17.9 joules

Explanation:

The quantity of Heat Energy (Q) required to heat solid silver depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass= 3.02g

C = 0.24J/g°C

Φ = (Final temperature - Initial temperature)

= 47°C - 22.3°C = 24.7°C

Then, Q = MCΦ

Q = 3.02g x 0.240J/g°C x 24.7°C

Q = 17.9 Joules

Thus, 17.9 joules of heat isrequired.

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What is the mass of 2.70 ×10^22 molecules of NaOH (Molar mass = 40.0 g/mol)?
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Data:
Molar Mass of NaOH = 40 g/mol

Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules

6.02*10²³y = 0.270*10²³ 
y =  \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}
\boxed{y \approx 0.04\:mol}


Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH

x = 40*0.04
\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark

Answer:
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