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ozzi
3 years ago
9

1 point

Chemistry
1 answer:
Dafna1 [17]3 years ago
4 0
I’m pretty sure it’s true :))!!
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explain why the sun appers to be the brightest star in the sky. relate your explanation with an example such as street lights. t
Zarrin [17]

Answer:

The sun is a star but It is the brightest in the sky because it is the closest star to earth.

I don't know how to compare it to street lights though...

Explanation:

7 0
3 years ago
(a) Kw = 1.139 × 10⁻¹⁵ at 0°C and 5.474 × 10⁻¹⁴, find [H₃O⁺] and pH of water at 0°C and 50°C.
kondor19780726 [428]

The  value of [H₃O⁺] and  pH of water at 0°C and 50°C.

0°C value of [H₃O⁺] = 3.375 x 10⁻⁸

50°C value of [H₃O⁺]  = 2.340 x 10⁻⁷

pH of water at 0°C  =  pH = 7.4717

pH of water at 50°C  =  pH  = 6.6308

<h3>pH of water at different level:</h3>

Water with a pH less than 7 is considered acidic, while water with a pH greater than 7 is considered basic. The normal pH range for surface water systems is 6.5 to 8.5, and for groundwater systems is 6 to 8.5. Alkalinity is a measure of a water's ability to withstand a pH change that would cause it to become more acidic.

<h3>According to the given information:</h3>

0°C  =  Kw = 1.139 × 10⁻¹⁵

50°C = 5.474 × 10⁻¹⁴

Solving at  0°C  for  [H₃O⁺] and pH. water is neutral therefore its[H₃O⁺] [OH⁻]

are equal [H₃O⁺] = [OH⁻].

                                                Kw  =  [H₃O⁺] [OH⁻]

                                                  Kw  =  [H₃O⁺]²

                                                  [H₃O⁺] =  √Kw

                                                            =  √1.139 × 10⁻¹⁵

                                                            = 3.375 x 10⁻⁸

                                                pH = -log[H₃O⁺]

                                                      = -log 3.375 x 10⁻⁸

                                                      = 7.4717

Solving at  50°C  for  [H₃O⁺] and pH. water is neutral therefore its[H₃O⁺] [OH⁻]

are equal [H₃O⁺] = [OH⁻].

                                                 Kw  =  [H₃O⁺] [OH⁻]

                                                  Kw  =  [H₃O⁺]²

                                                  [H₃O⁺] =  √Kw

                                                             = √ 5.474 × 10⁻¹⁴

                                                            = 2.340 x 10⁻⁷ M

                                                 pH = -log[H₃O⁺]

                                                       =  -log2.340 x 10⁻⁷

                                                   pH  = 6.6308

The  value of [H₃O⁺] and  pH of water at 0°C and 50°C.

0°C value of [H₃O⁺] = 3.375 x 10⁻⁸

50°C value of [H₃O⁺]  = 2.340 x 10⁻⁷

pH of water at 0°C  =  pH = 7.4717

pH of water at 50°C  =  pH  = 6.6308

To know more about pH of water visit:

brainly.com/question/13822050

#SPJ4

I understand that the question you are looking for is:

Kw = 1.139 × 10⁻¹⁵ at 0°C and 5.474 × 10⁻¹⁴, find [H₃O⁺] and pH of water at 0°C and 50°C. find the  [H₃O⁺] and  pH of water at 0°C and 50°C.

 

3 0
1 year ago
What is another name for the sugars organisms use for energy?1. Proteins2. Nucleic acids3. Carbohydrates4. Lipids
victus00 [196]

Answer:

Carbohydrates or Carbs have sugar molecules! :3 hope this helped you

Explanation:

4 0
3 years ago
using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius​
lukranit [14]

Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

  • Answer: <u>5.5g</u>

Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

5 0
3 years ago
Which of the following is a property of a pure substance?
wolverine [178]
D.) the original components retain their individual properties
8 0
3 years ago
Read 2 more answers
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