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Dima020 [189]
4 years ago
12

What is the lowest mass that an object can have and still be a star?

Physics
1 answer:
CaHeK987 [17]4 years ago
5 0

Answer:

The lowest mass that an object can have to be considered a star is 0.08 solar masses.    

Explanation:

A star is get when it reaches the necessary temperature in its core to nuclear reaction began.

A Nuclear reaction is the fusion of lighter elements into heavier elements.

In stars there is an equilibrium between two forces, the force of gravity in the inward direction due to its own mass and the radiation pressure in the upward direction as a consequence of the nuclear reaction in its core, which is known as hydrostatic equilibrium.

Therefore, the mass of the star must be enough to the force of gravity act in the inward direction, which leads to the increase in pressure, density and of course temperature in the core, allowing the nuclear reaction to begin.

Hence, the lowest mass that an object can have to be consider a star is 0.08 solar masses.    

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A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate
Mrac [35]

Explanation:

It is given that,

The angle of projection is 60 degrees

Initial velocity of the ball is 120 m/s

We need to find the time taken to get to the maximum height and the time of flight.

Time taken to reach the maximum height is given by :

T=\dfrac{u^2\sin^2\theta}{2g}

g is acceleration due to gravity

T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s

(ii) Time of flight,

t=\dfrac{2u\sin\theta}{g}

So,

t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s

Hence, this is the required solution.

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3 years ago
The friends take a few minutes to discuss their ideas. Which of Amy's comments with respect to a charged particle moving in a ma
Marizza181 [45]

Answer:

The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false.

Explanation:

The equation for the magnetic force on a charge q moving at velocity v on a magnetic field B is given by the (vectorial) Lorentz Force Law F=qv\times B

From it we can clearly see that the <em>magnitude of the magnetic force </em>exerted on the particle is <em>proportional to the magnitude of the charge q and to the speed v of the particle</em>, and that it is also <em>perpendicular to the particle's velocity</em>. This means that at each instant it moves perpendicularly to the force, so <em>the work done by the magnetic force on the particle is zero</em>.

The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false not only for this but for any force, a force always perpendicular to a velocity will curve the trajectory.

7 0
3 years ago
You have a sealed glass jar full of air. If you put it in the freezer, what happens to the gas pressure in the jar?
xz_007 [3.2K]
The pressure inside decreases
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emmainna [20.7K]

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Explanation: nice face.

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denis-greek [22]

Answer:

No, it's not there.

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3 years ago
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