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KiRa [710]
3 years ago
11

A space station consists of three modules, connected to form an equilateral triangle of side length 82.0 m. Suppose 100 people,

with an average mass of 75.0 kg each, live in each capsule and the mass of the modules is negligible compared to the mass of the people. At the current rotational rate the effective acceleration of gravity is g/2. (a) What angular momentum of the system
Physics
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

Angular momentum of the system is 16221465.4617 kgm²/s

Explanation:

Given that;

length of the side of the triangle L =  82 M

m = 75.0 kg × 100 = 7500 kg

distance of each vertex from center R = L/√3 = 82/√3 = 47.34 m

effective acceleration a = 9.8 / 2 = 4.9 m/s²

we know that; effective acceleration is being provided by centripetal acceleration.

so

a = R × w²

rate of rotation w = √( a / R) = √( 4.9 / 47.34)  = 0.3217 rad/seconds

Moment of Inertia I = 3mR²

we substitute

I = 3 × 7500 × (47.34)²

Also, Angular momentum L is expressed as;

L = I × w

so

L = 3 × 7500 × (47.34)² × 0.3217

L =  16221465.4617 kgm²/s

Therefore, Angular momentum of the system is 16221465.4617 kgm²/s

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The answer to your question is TWICE AS GREAT
5 0
4 years ago
When cooking frozen cheese ravioli, the directions say to put the 255 grams of filled pasta into 3 quarts of boiling water. Why
nadya68 [22]

Answer:

a. T_f=95.14^{\circ}C

b. T_f=86.4^{\circ}C

It is asked for 3 quarts of water  because it prevents the temperature drop.

Explanation:

Given:

  • mass of frozen cheese, m_c=255\ g
  • quantity of water suggested for the given cheese, m_w=3\ quarts\times 946.35=2839.05\ g
  • initial temperature of cheese, T_{ic}=-40^{\circ}\ C
  • specific heat of cheese, c_c=0.4\ cal.g^{-1}.^{\circ}C^{-1}
  • initial temperature of water, T_{iw}=100^{\circ}\ C

a.

  • we have specific heat of water, c_w=1\ cal.g^{-1}.^{\circ}C^{-1}

so now, we use the heat equation to find the amount of heat exchange during the process:

m_c\times c_c\times \Delta T=m_w\times c_w\times \Delta T

255\times 0.4\times (T_f-(-40))=2839.05\times 1\times (100-T_f)

T_f=95.14^{\circ}C

b.

when using 1 quart of water:

255\times 0.4\times (T_f-(-40))=946.35\times 1\times (100-T_f)

T_f=86.4^{\circ}C

It is asked for 3 quarts of water  because it prevents the temperature drop.

3 0
3 years ago
The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond ?​?
zepelin [54]

Answer:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

5 0
3 years ago
Which of the following accurately describe some aspect of gravitational waves? Select all that apply.
steposvetlana [31]
<h2>Answers:</h2>

-The first direct detection of gravitational waves came in 2015

-The existence of gravitational waves is predicted by Einstein's general theory of relativity

-Gravitational waves carry energy away from their sources of emission

<h2>Explanation:</h2>

Gravitational waves were discovered (theoretically) by Albert Einstein in 1916 and "observed" for the first time in direct form in 2015 (although the results were published in 2016).  

These gravitational waves are fluctuations or disturbances of space-time produced by a massive accelerated body, modifying the distances and the dimensions of objects in an imperceptible way.  

In this context, an excellent example is the system of two neutron stars that orbit high speeds, producing a deformation that propagates like a wave,<u> in the same way as when a stone is thrown into the water</u>. So, in this sense, gravitational waves carry energy away from their sources .

Therefore, the correct options are D, E and F.

5 0
4 years ago
a light bulb has a resistance of 360 . what is the current in the bulb when it has a potential difference of 120 v across it? 0.
xenn [34]
Presume we are looking for the current:

V = IR

120 = I*360

120/360 = I

1/3 = I

I = 1/3 = 0.333..

Current ≈ 0.33 Ampere.
7 0
3 years ago
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