Answer:
(a). The final volume is 2.5 times the initial volume.
The work done is 1143 J.
(b). The final temperature is 207.9 K
The work done is 574 J.
Explanation:
Given that,
Sample of an ideal gas = 0.500 mol
Initial pressure = 400 kPa
Final pressure = 160 kPa
Temperature = 300 K
(a) for isothermal,
Temperature will be same.
We need to calculate the volume of gas
Put the value into the fomrula
We need to calculate the work done
Using equation of energy
(b). For adiabatic,
No transfer of heat between system and surroundings
We need to calculate the final temperature
Using formula of gas
Put the value into the formula
We need to calculate the wok done in adiabatic
Using formula of work done
Hence, (a). The final volume is 2.5 times the initial volume.
The work done is 1143 J.
(b). The final temperature is 207.9 K
The work done is 574 J.