Explanation:
<h3>oxidation of Nitrogen in N2O3 is </h3><h2>+3</h2>
Answer:
the initial temperature of the iron sample is Ti = 90,36 °C
Explanation:
Assuming the calorimeter has no heat loss to the surroundings:
Q w + Q iron = 0
Also when the T stops changing means an equilibrium has been reached and therefore, in that moment, the temperature of the water is the same that the iron ( final temperature of water= final temperature of iron = T )
Assuming Q= m*c*( T- Tir)
mc*cc*(T-Tc)+mir*cir*(T - Tir) = 0
Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )
Tir = 90.36 °C
Note :
- The specific heat capacity of water is assumed 1 cal/g°C = 4.186 J/g°C
- We assume no reaction between iron and water
The answer would be A, 100g since it’s equal
Answer:
C. the number of atoms, molecules, ions, formula units, or other particles in a mole of a substance
Explanation: Its correct
Answer:
0.054 M
Explanation:
1 mol NaHSO4 -> 120 g
x ->13 g
x= 0.108 mol NaHSO4
M= mol solute/ L solution
M= 0.108 mol NaHSO4/ 2.00L
M= 0.054 M
