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ValentinkaMS [17]
3 years ago
12

How many grams are there in 3.4 x 10^24 atoms of He?

Chemistry
1 answer:
Lelechka [254]3 years ago
5 0

Given :

Number of He atoms, n = 3.4\times 10^{24} atoms.

To Find :

How many grams are their in given number of He atoms.

Solution :

We know, molecular mass of He is 4 g. It means that their are 6.022 \times 10^{23} atoms in 4 g of He.

Let, number of gram He in 3.4\times 10^{24} atoms is x , so :

x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x =  $$22.58\ g

Therefore, grams of He atoms is 22.58 g .

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Solution:

By the following ways the polar molecule doesn’t mix with non-polar molecule  

Polar molecules have a portion of their molecule which, relative to the rest of the molecule, is more negative.  

Water, for example, has a bent, or V-shape, due to the 2 lone electron pairs on oxygen. This makes the oxygen end more negative than the hydrogen end. This negative area allows for hydrogen bonding between that molecule and other molecules which are also polar.  

Non-polar molecules don't have a portion of the molecule which is more negative than the rest. An example of this is a hydrocarbon, like butane. Because there is no relatively negative region to the molecule, it cannot partake in hydrogen bonding and therefore does not mix with polar molecules.  

Thus we can conclude that Polar mixes with polar; non-polar mixes with non-polar.


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Then you can modifiy the density of a material by either affecting the mass or the volume.

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Then the answer is decrease the mass or increase the volume, while the other is kept constant.

Explanation:

The density is the relation mass/volume.

Then you can modifiy the density of a material by either affecting the mass or the volume.

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Also, you can decrease the mass while keeping the volume constant to decrease the density (because you are decreasing the numerator of the fraction).

Then the answer is decrease the mass or increase the volume, while the other is kept constant.

Read more on Brainly.com - brainly.com/question/1832775#readmore

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An analogy to define the term half-life?
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Hey there!:

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