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lana [24]
3 years ago
8

Amino acids are monomers that join together in complex macromolecules called _____.

Chemistry
2 answers:
UkoKoshka [18]3 years ago
8 0
Answer is B. proteins

Amino acids are building blocks in
proteins.
Proteins play numerous roles in cellular processes.
dezoksy [38]3 years ago
4 0
Proteins is a amino acids are monomers that join together in complex macromolecules.
Answer is B.
Hope it helped you.
-Charlie
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A gas is contained in a 5.0–liter container at a pressure of 100 kPa. What size container would be required to contain the gas a
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When volume and pressures are given, it means we need to use Boyles' law formula--> P1V1 = P2V2

P1= 100 kPa
V1= 5.0 L
P2= 50 kPa
V2= ???

let's plug in the values.

(100 x 5.0) = (50 x V2)

V2= 10 L
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What is an input force?
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4 years ago
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How many grams are in 0.36 moles of CCl4
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Answer:

We assume you are converting between moles CCl4 and gram. You can view more details on each measurement unit: molecular weight of CCl4 or grams This compound is also known as Carbon Tetrachloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CCl4, or 153.8227 grams.

Explanation:

Hope this helps :)

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3 years ago
A car rolls down a ramp. What is the force acting on the car that causes the movement down the ramp?
Komok [63]
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4 years ago
Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a
slega [8]

Answer:

\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}

From Equation (2), the molar ratio of iodine to thiosulfate is

\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}

Combining the two ratios, we get

\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}

7 0
3 years ago
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