Answer:
Q = - 8501.99 j
Explanation:
Given data:
Specific heat of Al = 0.902 j/g.°C
Heat lost = ?
Mass of sample = 23.984 g
Initial temperature = 415°C
Final temperature = 22°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 22°C - 415°C
ΔT = -393°C
Q = m.c. ΔT
Q = 23.984 g× 0.902 j/g.°C × -393°C
Q = - 8501.99 j
The answer is B. Lithosphere
Explanation: The upper layer of mantle is a zone of rigid brittle rock. Below the lithosphere is asphalt-like and is called the Asthenosphere.
Answer:
diluted or stronger
Explanation:this is caused by the addition of oxygen and it is normally overbearing of ends up changing the whole molecule
Explanation:
A dependent variable depends on the independent variable. The independent variable is what you usually control in a experiment.