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givi [52]
3 years ago
10

Urgent!! I need this to pass the lesson.

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0

the first one is 8. the second one is 18. the third one is 15.

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Elen planned to read a book of 40 pages in two days. On the first day, she read 4 hours reading 7 pages per hour. On the second
amm1812

Ok so 7 times 4 is 28 so she read 28 the first day. For the second day since 40-28= 12, 12 divided by 2 is 6. So she read 6 pages per hour.

7 0
3 years ago
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Solve the equation.<br> 10x-8/3-4x=6x<br> help plz
butalik [34]

Answer:

its 1/3

Step-by-step explanation:

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3 years ago
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randy has two 28 pound blocks of ice for his snow cone stand .if each snow requires  2/3  pound of ice ,how many snow cones can
nadezda [96]
Two 28 pound blocks of ice = 28 x 2 = 56
56 x 2/3 =112/3=37.33333
we round it to 37. so it's about 37 cones can be made
3 0
4 years ago
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Dose this graph represent a function?why or why not?
Nikitich [7]
In order for a function...to be called a function , is that for every x, there must always only be one y. Two x's can have the same y, but the same x can't have two separate y's. One way to test this is the vertical line test. You basically put up a vertical line on the graph. The artificial line (you can do it with your finger, pencil, etc.) should only intersect once on the graph. So, take your pencil, and hold it up to down (like this | ) on your monitor. You see that when you do that, it intersects with the graph twice. That means it DOESN'T pass the vertical line test, which means it is not a function (Function are not always straight lines, which is why the first two are wrong). So, the answer is 

D)
5 0
4 years ago
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Do not use your calculator for Parts 1 through 4.
Hunter-Best [27]
You have to understand how piecewise functions first
I hope you do because I won't be explaining it here



1.
if it is continiuous at x=1 then the part of the function that approaches 1 from the left is the same value
so we have f(x)=3-x for x<1, so evaluate it for x=1,
we would get 3-1=2
so
if a=2 and b=3

f(x)=2x²+3x
for x=1, we get 2+3=5

it approaches 2 from the left but equals 5
2≠5
so it is not continuous because it doesn't approach the same value at x=1




2.
alright
so we established that it should approach 2 because we had the f(x)=3-x
so
f(1)=2=ax²+bx
2=a+b
the relationship is 2=a+b



3.
same as before, but use the other function, the one that is defined at x≥2
5x-10, 5(2)-10, 10-10, 0
it approaches 0
so
we must find one such that f(x)=0 for x=2 with the ax²+bx
0=a(2)²+b(2)
0=4a+2b
if we minus 2b both sides
-2b=4a
divide by 2
-b=2a
add b both sides
0=2a+b



4.
2=a+b
0=2a+b

2=a+b
minus b both sides
2-b=a
subsitute
0=2a+b
0=2(2-b)+b
0=4-2b+b
0=4-b
b=4

sub back
2-b=a
2-4=a
-2=a

a=-2
b=4


5.
graph f(x)=-2x²+4x from x=1 to x=2 and put a closed dot at (1,2) and an open dot at (2,0)
4 0
3 years ago
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