Unlike solid matter, where particles are tightly packed and slightly vibrating, or gas, where particles go around everywhere and are extremely loose, a liquid has particles that are loosely packed but are still in slight contact with each other. Hope that's good enough
Carbon monoxide (CO) is the name
Answer:
Sr would be the limiting reactant
5 moles
Explanation:
Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.
Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.
Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.
From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.
When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.
For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.
Molarity= mol/ liters
since the molarity is given, we can assume that we have 1.0 Liters of solution
15.6 M= mol/ 1 liters---> this means that we have 15.6 moles of HNO3
we need to convert these moles to grams using the molar mass of HNO3
molar mass HNO3= 1.01 + 14.0 + (3 X 16.0)= 63.01 g/mol
15.6 mol HNO3 (63.01 g/ mol)= 983 grams HNO3
now we have to determine the grams of solution using the assumption of 1 liters of solution and the density
1 liters= 1000 mL
1000 mL (1.41 g/ ml)= 1410 grams solution
mass percent= mass of solute/ mass of solution x 100
mass percent= 63.01/ 1410 x 100= 4.47 %
