Carbon and Hydrogen are present in all organic compounds !
When the flip flops are used to walk on the ground the sulfuric acid from the ground overtime tends to wear down the bottom of the flip flops
Answer: (a) pH = 4.774, (b) pH = 4.811 and (c) pH = 4.681
Explanation: (a) pH of the buffer solution is calculated using Handerson equation:

pKa for acetic acid is 4.76. concentration of base and acid are given as 0.95M and 0.92M. Let's plug in the values in the equation and calculate the pH of starting buffer.

pH = 4.76 + 0.014
pH = 4.774
(b) When 0.040 mol of NaOH (strong base) are added to the buffer then it reacts with 0.040 mol of acetic acid and form 0.040 mol of sodium acetate.
Original buffer volume is 1.00 L. So, the original moles of sodium acetate will be 0.95 and acetic acid will be 0.92.
moles of acetic acid after addition of NaOH = 0.92 - 0.040 = 0.88
moles of sodium acetate after addition of NaOH = 0.95 + 0.040 = 0.99
Let's again plug in the values in the Handerson equation:

pH = 4.76 + 0.051
pH = 4.811
(c) When 0.100 mol of HCl are added then it reacts with exactly 0.100 moles of sodium acetate(base) and form 0.100 moles of acetic acid(acid).
so, new moles of acetic acid = 0.92 + 0.100 = 1.02
new moles of sodium acetate = 0.95 - 0.100 = 0.85
Let's plug in the values in the equation:

pH = 4.76 - 0.079
pH = 4.681
Answer:
The molecular formula of the compound = 
The empirical formula of the compound = 
The balanced chemical equation for this reaction:

Explanation:
Compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.
Molar mass of compound = 444.56 g/mol
Number of phosphorus atom = x
Number of sulfur atom = y
Atomic mass of phosphorus 31 g/mol
Atomic mass of sulfur = 32 g/mol
Percentage of element in compound :

Phosphorus :

x = 4
Sulfur :

y = 10
The molecular formula of the compound = 
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
The empirical formula of the compound = 
The balanced chemical equation for this reaction:
