Answer:
He did not do it very well.
Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length
![\Delta L=L_{2}-L_{1}](https://tex.z-dn.net/?f=%5CDelta%20L%3DL_%7B2%7D-L_%7B1%7D)
![\Delta L=74.7-58.6](https://tex.z-dn.net/?f=%5CDelta%20L%3D74.7-58.6)
![\Delta L=16.1\ m](https://tex.z-dn.net/?f=%5CDelta%20L%3D16.1%5C%20m)
For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength
![\lambda=2\Delta L](https://tex.z-dn.net/?f=%5Clambda%3D2%5CDelta%20L)
Put the value into the formula
![\lambda=2\times16.1](https://tex.z-dn.net/?f=%5Clambda%3D2%5Ctimes16.1)
![\lambda=32.2\ cm](https://tex.z-dn.net/?f=%5Clambda%3D32.2%5C%20cm)
We need to calculate the frequency of the tuning
Using formula of frequency
![f=\dfrac{v}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D)
Put the value into the formula
![f=\dfrac{343}{32.2\times10^{-2}}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B343%7D%7B32.2%5Ctimes10%5E%7B-2%7D%7D)
![f=1065.2\ Hz](https://tex.z-dn.net/?f=f%3D1065.2%5C%20Hz)
![f=1.065\ kHz](https://tex.z-dn.net/?f=f%3D1.065%5C%20kHz)
Hence, The frequency of the tuning is 1.065 kHz
Answer:
<h2>Rotational inertia first decreases and then increases as the satellite is ready to land</h2>
Explanation:
This problem is based on the conservation of angular momentum.
<h2>What is the Law of Conservation of Angular Momentum
?</h2>
The Law of Conservation of Angular Momentum states that
<em>"The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point".</em>
The rate of rotation increases greatly when the Satelite is moved inwards by 10%, decreasing the moment of inertia. The work-done to pull in the Satelite results in an increase in rotational kinetic energy.
The work done by the machine is equal to the product between the force applied and the distance over which the force is applieds, so in this case:
![W=Fd=(3 N)(9 m)=27 J](https://tex.z-dn.net/?f=W%3DFd%3D%283%20N%29%289%20m%29%3D27%20J)
And the power of the machine is equal to the ratio between the work done by the machine and the time taken:
I am pretty sure that if a star has no measurable parallax it means that it is placed on unreachable distance so that you need a special equipment in order to get closer and measure <span> parallax. The point is that it is placed too deep in space and you are not able to measure it with basic equip.
Hope that helps.
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