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Aleks04 [339]
3 years ago
7

Which tool would you use to measure the amount of rainfall?

Physics
2 answers:
alina1380 [7]3 years ago
8 0

Answer:

A. Graduated Cylinder

Explanation:

A thermometer would just tell you the temperature.

A scale would just tell you how much it weighs.

And a stop watch would do nothing but show numbers until it got wet enough and broke.

The only logical answer is A since it is also a measuring flask WITH incriments already on the side of it to tell you how much water you collect.

Hope this helps!!

zheka24 [161]3 years ago
5 0

Answer:

a

Explanation:

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The ______ clause in an if statement allows a program to make one choice if the condition is true, and anothere choice if the co
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Answer: The IF clause.

Explanation: This is the IF clause; you can use it as:

IF (something = true) then "something happens"

else "other thing happens"

Some example of it can be, suppose that your program reads a number X that the user inputs, then you can do:

If ( X > 5) then

print: "the number X is bigger than five"

Else

print: "the number X is smaller than five"

Where, of course, the statements depend on the language used, but the "if" clause works almost the same in every language.

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True Edg2020

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The caterpillar had to move across the horizontal segments. I hope this helps :)

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Do transparent objects absorb light?
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A scientist fixes a test charge q′ to point P and then measures the electrostatic force it experiences there. She then calculate
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Answer:

<em>Correct answer: B.</em>

Explanation:

Electrostatic Field

It measures the electric effect of a charge distribution in its surroundings. If we wanted to test or measure the electric field by using a point-charge of value q', then the electric field is

\displaystyle E=\frac{F}{q'}

The electrostatic force between two point charges is

\displaystyle F=\frac{k\ q_1\ q'}{r^2}

So, the electric field is

\displaystyle E=\frac{\frac{k\ q_1\ q'}{r^2}}{q'}

\displaystyle E=\frac{k\ q_1}{r^2}

The theory shows that the electric field doesn't depend on the test charge used, i.e., if we now use q'=-q', the electric force will be of the same magnitude but in the opposite direction, thus the electric field will be the same. Let's recall the formula is used to compute the scalar value of the field, the direction must be studied separately.

Now, if we changed the test charge to another value, say 2q, the measured force will be

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\displaystyle E=\frac{k\ q_1}{r^2}

We can see the electric field is not affected by the value of the test charge.

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