Answer:
The allowable values for the principle quantum number (n) are integers greater than zero.
The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.
The allowable values for the magnetic quantum number (ml) are integers from -l to l.
The allowable values for the spin quantum number (ms) are -1/2 and 1/2.
Explanation:
<em>Identify allowable combinations of quantum numbers for an electron. Select all that apply.</em>
- <em>The allowable values for the principle quantum number (n) are integers greater than zero. </em>TRUE. The principal quantum number (n) represents the level of energy in which an electron is and can take positive integer values.
- <em>The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.</em> TRUE. The angular quantum number (l) represents the sublevel of energy and the kind of orbital an electron is in and can take integer values from 0 to n-1. For instance, if n = 1, l can take the value "0", which represents the sublevel and orbital "s".
- <em>The allowable values for the magnetic quantum number (ml) are integers from -l to l.</em> TRUE. The magnetic quantum number (ml) represents the orientation of an orbital in space and can take integers values from -l to +l. For instance, if l = 1 (p orbital), ml can take the values -1, 0 and 1, which refer to orbitals px, py and pz.
- <em>The allowable values for the spin quantum number (ms) are -1/2 and 1/2. </em>TRUE. The spin quantum number (ms) represents the spin of the electron and can take values -1/2 and +1/2.
Hey there!
Just say what color you think the mixture would look like if those elements were combined. Personally I don't know because I don't have context, but if it comes to it just pick a color :)
Good luck, have a good night.
Hey there!
No of hybrid orbitals , H = ( V +S - C + A ) / 2
Where H = no . of hybrid orbitals
V = Valence of the central atom = 5
S = No . of single valency atoms = 4
C = No . of cations = 1
A = No . of anions = 0
For PCl4 +
Plug the values we get H = ( 5+4-1+0) / 2
H = 4 ---> sp3 hybridization
sp3 hybrid orbitals are used by phosphorous in the PCl4+ cations
Answer C
Hope that helps!
It’s easy, if the PH of any acidic solution = -Log[H+], where [H+] is hydrogen ion concentration, multiply each term by (-1) then raise each term as a power to (10), so it will become like this:-
[H+] = 10^(-PH)
Answer:
atomic number
Explanation:
atomic number is the number of protons
