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AlexFokin [52]
3 years ago
9

What is the configuration of all electron pairs arranged around oxygen in a water molecule? bent trigonal planar tetrahedral lin

ear
Chemistry
1 answer:
jek_recluse [69]3 years ago
6 0
I think the answer would be : Tetrahedral

Oxygen has 6 electrons and need 2 more electron to complete its octet.  In Tetrahedral, the electrons are arranged so it surround the oxygen and forming a 109 degree bond angel/

hope this helps
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A voltaic cell using Cu/Cu²⁺ and Sn/Sn²⁺ half-cells is set up at standard conditions, and each compartment has a volume of 345 m
Nadusha1986 [10]

The mass of copper deposited is 9.589 g .

Given ,

A volatile cell using Cu/Cu2+ and Sn/Sn2+ half cells is set up at standard conditions ,and each compartment has a volume of 345 ml .

current = 0.17 A

time = 48 hrs =48 (60) (60) =172800 sec

we know , I = Q/t

thus , Q ,charge= It = 0.17 (17280) =29376 C

Then ,atomic mass of copper is 63 g

And valency of Cu is 2.

Thus , the equivalent mass of copper is 63/2 = 31.5

We know , 96500 coulombs of electricity produce copper = 31.5 g

29376 C of electricity produce copper =9.589 g

Hence , 9.589 g of Copper is deposited .

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4 0
2 years ago
LINKS WILL BE BLOCKED AND REPORTED PLS HELP
PtichkaEL [24]

Answer: c

Explanation: c.

7 0
3 years ago
The number 0.000402 expressed in scientific notation is
goldfiish [28.3K]

Answer:

hope its help you

Explanation:

4.02 x 10-4

3 0
3 years ago
How would this atomic structure change if you built an atom of Krypton which has an atomic number of 36?
jenyasd209 [6]

Answer:

Explanation:

d

5 0
3 years ago
Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i
Goshia [24]

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and 3.073\times 10^4kJ/L respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

\Delta H^o_{comb}=-3535kJ/mol

Fuel value = \frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}

Molar mass of pentane = 72 g/mol

Fuel value = \frac{3535kJ/mol}{72g/mol}

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = 3.073\times 10^4kJ/L

Thus, the fuel density of pentane is 3.073\times 10^4kJ/L

4 0
4 years ago
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