The question is incomplete, here is the complete question:
Consider the following reaction:
In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?
<u>Answer:</u> The average rate of appearance of oxygen gas is
<u>Explanation:</u>
We are given:
Moles of oxygen gas =
Volume of solution = 0.480 L
Molarity is calculated by using the equation:
So,
The given chemical reaction follows:
The average rate of the reaction for appearance of is given as:
Or,
where,
= final concentration of oxygen gas = 0.0396 M
= initial concentration of oxygen gas = 0 M
= final time = 15.0 s
= initial time = 0 s
Putting values in above equation, we get:
Hence, the average rate of appearance of oxygen gas is