Answer:
The answer is 0.75M HCl
Explanation:
To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:
To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:
C1V1 = C2V2
C1 = concentration of acid
C2 = concentration of base
V1 = volume of acid
V2 = volume of base
From the information supplied in the question:
concentration of acid (HCl) is the unknown
volume of acid (HCl) = 10ml
concentration of base (NaOH) = 0.15M
volume of base (NaOH) = 50ml
C1 x 10ml = 0.15M x 50ml
C1 x 10 = 7.5
divide both side by 10
C1 = 0.75M
concentration of acid (HCl) is 0.75M
<span>Here we are asked to know the type of bond
between a glycosidic bond. A glycosidic bond is a type of bond that
exists between a carbohydrate molecule to another carbohydrate molecule. A
glycosidic bond creates between two monosaccharides can also be called as an
ether bond.</span>
Answer: 1 mol of 
will be produced from this reaction.
Explanation: Reaction follows,
As seen from the balanced chemical equation above, we get
For every 3 moles of Aluminium and 3 moles of 
, 1 mole of 
is formed.
For every 3 moles of Aluminium and 3 moles of , 1 mole of is formed.
For every 3 moles of Aluminium and 3 moles of , 3 moles of 
is formed.
For every 3 moles of Aluminium and 3 moles of , 6 moles of 
is formed.
Answer:
1.6666666666666 is the ans bcz in each mole there r 12 grams of carbon so the ans is goingtobe 20÷12
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