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2 years ago

013 10.0 points

Chemistry

1 answer:

34kurt2 years ago

5 0

Answer:

this isn't immediately clear, it can be seen in ... CO2? 1. 6.0 × 10−23 g. 2. 44 g. 3. 7.31 × 10−23 g correct. 4. 6.0 × 10. 23 g. 5. 7.31 × 10 ... 40.0 grams of S will react leaving 10.0 grams. S unreacted. 013. 10.0 points ... FeCl2 and K2CO3 is ... 9. 1. There is no reaction. 2. KCl electrolyte. 3. CO2 gas. 4. FeCO3 precipitate. correct.

Explanation:

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Explain how matter changes from one state to another such as liquid

beks73 [17]

Answer:

When heated or cooled, matter can transform from one state to another. When you heat ice (a solid), it turns into water (a liquid). MELTING is the term for this transformation. When water is heated, it becomes steam (a gas).

Explanation:

i hope thats the answer you want

8 0

1 year ago

According to table g, which substance forms an unsaturated solution when 80. grams of the substance are stirred into 100. grams

e-lub [12.9K]

A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.

Unsaturated solution has solute in lower proportions than required to form a saturated solution.

Supersaturated solution has solute in amounts greater than a saturated solution.

We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.

The solubility of KI at 10 $^{0}C$ is 136 g/ 100 mL water

The solubility of $KNO_{3}$ at $10^{0}C$ is 21 g/100 mL water.

The solubility of $NaNO_{3}$ at $10^{0}C$ is 80 g/100 mL water.

The solubility of NaCl at $10^{0}C$ is 38 g/ 100 mL water.

So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at $10^{0}C$ .So, if we have 80g KI/ 100mL water it would be an unsaturated solution.

4 0

3 years ago

Read 2 more answers

1. Express in conventional notation (no exponents) in the space provided within the

mina [271]

Answer:

a) 320: two significant figures.

b) 2,366: four significant figures.

c) 73.0: three significant figures.

d. 532.5: four significant figures.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to write each number by knowing we move the decimal places to the right as much as the exponent is, and also, we count every figure, even zeros, because they are to the right of the first nonzero digit:

a) 320: two significant figures because the rightmost zero is not preceded o followed by a decimal place.

b) 2,366: four significant figures.

c) 73.0: three significant figures, because the zero is followed by the decimal place.

d. 532.5: four significant figures.

Regards!

7 0

3 years ago

The most common element in the atmosphere are

Ivanshal [37]

Nitrogen and oxygen are the most prevalent in the atmosphere.

8 0

3 years ago

Create the Lewis structure of CF4. NOTE: do only the step asked for in each part and then click Check–don't work ahead to solve

Naya [18.7K]

To create the Lewis structure we need to take into account the octet rule: atoms tend to gain, lose or share electrons to complete their valence shell with 8 electrons.

C belongs to Group 4A in the periodic table so it has 4 valence electrons. It needs to share 4 pairs of electrons to complete the octet.

F belongs to Group 7A in the periodic table so it has 7 valence electrons. Each F needs to share 1 pair of electrons to complete the octet.

As a consequence, in CF₄, C will form a single bond with each F and all the octets will be complete.

5 0

3 years ago