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alexira [117]
3 years ago
10

What is the equation for force of friction

Physics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

that's your answer..

..f = \mu N

f = friction force

\mu = coefficient of friction

N = normal force

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yaroslaw [1]

Answer:

a)-2m/s^2

b)27.2m/s

Explanation:

Hello! The first step to solve this problem is to find the mass of the block remembering that the definition of weight force is mass by gravity (g=9.8m / s ^ 2)

W=455N=weight

W=mg

W=455N=weight

m=\frac{W}{g} =\frac{455}{9.81}=46.38kg

The second step is to draw the free body diagram of the body (see attached image) and use Newton's second law that states that the sum of the forces is equal to mass by acceleration

a=\frac{T-W}{m} =\frac{361-455}{46.38kg} =-2m/s^2

for point b we use the equations of motion with constant acceleration to find the velocity

Vf=\sqrt{X(2)(a)+Vo^2}

Where

Vf = final speed

Vo = Initial speed =0

A = acceleration =2m/s

X = displacement =6.8m

Solving

Vf=\sqrt{(6.8)(2)(2)+0^2}=27.2m/s

4 0
3 years ago
A rolling ball has an initial velocity of 1.6 meters per second. if the ball has a constant acceleration of 0.33 meters per seco
lukranit [14]
We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
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There are five constant acceleration equations that would help us to find the velocity:

v=u+at
s=ut+ \frac{1}{2}at^2
s= \frac{1}{2}(u+v)t
v^2=u^2+2as
s=vt- \frac{1}{2}at^2

Since we have u, a, t and we want v
We will use the first formula v=u+at

v=1.6+(0.33)(3.6)
v= 2.788 m/s
7 0
2 years ago
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dimulka [17.4K]
=1244 and that's from my math book
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2 years ago
4. Ano ang matinding suliranin ang kakaharapin kapag patuloy ang pagkasira ng
jasenka [17]

Answer:

I think its D

Explanation:

Kasi Pinoy ako

5 0
3 years ago
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F = m a 
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