Answer:
x = 7.14 meters
Explanation:
It is given that,
Current in wire 1, 
Current in wire 2,
Distance between parallel wires, r = 25 cm
Let at P point the net magnetic field equal to 0. The magnetic field at a point midway between the is given by :

Let the distance is x from wire 1. So,



x = 7.14 meters
So, the magnetic field will be 0 at a distance of 7.14 meters from wire 1. Hence, this is the required solution.
Answer:
f_2 = 436 Hz
Explanation:
Given:
- Frequency of the note played f_1 = 440 Hz
- Number of beats heard per second b = 4 Hz
Find:
What was the frequency of the mis-tuned A string?
Solution:
- The beat is the difference in frequency of the notes played and is given by the expression:
| f_1 - f_2 | = beats
- we heard 4 beats, so
| f_1 - f_2 | = 4
- Plug in the value: | 440 - f_2 | = 4
Hence, f_2 = 436 Hz
Answer:
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Explanation: