P(B) = 1 - P(B') = 1 - (7/12) = 5/12
<span>P(A∩B)=<span><span>P(A∩<span>B′</span>)/</span><span>P(<span>B′</span>) </span></span>× <span><span>P(B)/</span>1
</span></span>Plugging values into the last equation we get:
<span>P(A∩B)=<span><span>1×12×5 / </span><span>6×7×12 </span></span>= <span>542</span></span>
Now we can make use of the following formula
<span>P(A|B)=<span><span>P(A∩B) / </span><span>P(B)</span></span></span><span>
by plugging in the values that we have found.
</span>
<span>5/42 is the numerator and the denominator is 5/12.
</span>
The bottom (denominator) is P(B) which equals 5/12.
<span>P(A|B)=<span><span>5×12 / </span><span>42×5 = 6/210
6/210 = 2/7
</span></span></span><span>p(a[b]) = 2/7</span>
Answer:
heterogeneous genotype have two different Allels at a particular gene locus while a homogeneous have the same
Why dies???? what do you mean
1. Diffusion
2. Osmosis
3. Facilitated Diffusion
