A ball is thrown upward at a velocity of 19.6 m/s. What is its velocity after 3.0, assuming negligible air resistance?
2 answers:
Answer:
After 3 seconds the velocity becomes 49 m/s
Explanation:
Applying upward displacement equation:
differentiate this equation,
where; dy/dt is the velocity function;
After 3 seconds, the velocity becomes;
V = 19.6 + (9.8)(3)
V = 19.6 + 29.4
V = 49 m/s
Therefore, after 3 seconds the velocity becomes 49 m/s
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The amount of work done by two boys who apply 200 N of force in an unsuccessful attempt to move a stalled car is 0.
Answer: Option B
<u>Explanation: </u>
Work done is the measure of work done by someone to push an object from its present position. We can also define work done as the amount of forces needed to move an object from its present position to another position. So the amount of work done is directly proportionate to the product of forces acting on the object and the displacement of the object.
So in this present case, as the two boys have done an unsuccessful attempts to push a stalled car so that means the displacement of the car is zero as there is no change in the position of the car. But they have applied a force of 200 N each. So the amount of work done will be
Thus, the amount of work done by two boys will be zero due to their unsuccessful attempt to move a stalled car.