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Kryger [21]
3 years ago
6

What is similar about analogical and symbolic representations?

Physics
2 answers:
Otrada [13]3 years ago
7 0
<h2>Answer:</h2>

<u>Both of them are treated by brain in augmented form</u>

<h2>Explanation:</h2>

Symbolic representation is the representation in mind where the image of the object is made in brain such as if we say the word flower then the image of flower comes to our mind so the same thing can be done in practical form for the people who are deaf. Gestures are also the examples of symbolic representation. On the other hand analogical representation is usually a comparison between one thing and another, typically for the purpose of explanation or clarification. The image is not shown but the pre recorded image of the object is recalled in the memory and the brain realizes it. For example the word flower relates to the word beauty.

ICE Princess25 [194]3 years ago
3 0
Symbolic representations are mental pictures that have no direct relationship to the actual object you are thinking about. Instead, these mental pictures are connected by themes that are meaningful to you. Anytime you think of words and descriptions for one main concept, you're thinking symbolically. Analogical representations are mental pictures that have a direct relationship to the actual object you are thinking about. Do cows have their ears on the top or side of their heads? Rather than thinking symbolically about a cow and his ears (tiny, smelly, leather), analogical representations of the cow's ears involve thinking of an actual cow in your head.
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Answer:

Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them. This then continues and passes the energy from the hot end down to the colder end of the substance.

Explanation:

pls make me brainliest

6 0
3 years ago
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A car moving in a straight line starts at X=0 at t=0. It passesthe point x=25.0 m with a speed of 11.0 m/s at t=3.0 s. It passes
Agata [3.3K]

Answer:

Average velocity v = 21.18 m/s

Average acceleration a = 2 m/s^2

Explanation:

Average speed equals the total distance travelled divided by the total time taken.

Average speed v = ∆x/∆t = (x2-x1)/(t2-t1)

Average acceleration equals the change in velocity divided by change in time.

Average acceleration a = ∆v/∆t = (v2-v1)/(t2-t1)

Where;

v1 and v2 are velocities at time t1 and t2 respectively.

And x1 and x2 are positions at time t1 and t2 respectively.

Given;

t1 = 3.0s

t2 = 20.0s

v1 = 11 m/s

v2 = 45 m/s

x1 = 25 m

x2 = 385 m

Substituting the values;

Average speed v = ∆x/∆t = (x2-x1)/(t2-t1)

v = (385-25)/(20-3)

v = 21.18 m/s

Average acceleration a = ∆v/∆t = (v2-v1)/(t2-t1)

a = (45-11)/(20-3)

a = 2 m/s^2

8 0
3 years ago
You wad up a piece of paper and throw it into the wastebasket. How far will
astraxan [27]

Answer:

Since the paper is wadded up tight, and if there's any

air resistance left we assume there isn't any, it might

just as well be a stone that's tossed.  This is just a

stripped down projectile situation.

You said "an angle of 36 degrees", but you didn't say relative

to what.  I'll assume that it's 36 degrees above horizontal, and

now I'll proceed to answer the question with the information that

I just gave myself.

-- The vertical component of the velocity is  1.4 sin(36)

                                                                        = 0.823 m/s up.

-- The projectile rises for (0.823/9.8) second, runs out of gas,

and then falls for another (0.823/9.8) second to its original height.

So it's in the air for

                                  2 (0.823/9.8) = 0.168 second

                                                            (not very long at all)

-- The horizontal component of the velocity is  1.4 cos(36)

                                                                           = 1.133 m/s  

                                                             and it doesn't change.

-- During the 0.168 second that it's in the air,

the wad travels horizontally

                                              (0.168 s) x (1.133 m/s)

                                          =            0.19 meter

                                              (19 cm, ~ 7.5 inches)

If you find my mistake on this one, please please tell me.  

As of now, it looks like with that velocity at that angle, your

paper wad only makes it 7.5 inches from your hand into the can.

Explanation:

6 0
3 years ago
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Answer:

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A ball rolling on the ground

6 0
3 years ago
Assume that the Deschutes River has straight and parallel banks and that the current is 0.75 m/s. Drifting down the river, you f
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Answer:

    d = 142.5 m

Explanation:

This is a vector exercise. Let's calculate how much the boat travels in the 40s

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Let's write the kinematic equations

Boat

     x = d₀  +  v_{b} t

     x = 0 +  v_{h} t

At the meeting point the coordinate is the same for both

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    t ( v_{h} -  v_{b}) = d₀  

    t = d₀  / ( v_{b}-  v_{h})

The two go in the same direction therefore the speeds have the same sign

     t = 30 / (0.95-0.775)

     t = 150 s

The distance traveled by man is

     d =  v_{h} t

     d = 0.95 150

     d = 142.5 m

3 0
4 years ago
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