Answer:
The speed of the stone is
v = 7.45 m/s
Explanation:
Length, L=0.551m
maximum tension in the spring = 9.6%
So let speed of stone be
Tv = TH + 9.6/ 100 * TH
Tv - m*g = m*v^2/L
TH = m*v^2 / L
Factor mass to cancel in the equation
Solve to v
v^2= L*g*100 / 9.6
Replacing numeric:
v^2=0.551m*9.8m/s^2*100 / 9.6
v = sqrt( 56.24 m^2/s^2)
v = 7.45 m/s
Positive 2n to the right of the box
Answer:
Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.
Explanation:really sorry if it wrong,i mean reallyyyyy
Answer:
Option (d) is correct.
Explanation:
Work done is given by :
W = Fd, where F is force and d is displacement
Unit of work done :
The SI unit of force is Newton (N) and that of displacement is meter (m). So, the unit of work done is N-m. It is call Joule. It means that the unit of work done is Joule.
Power is given by rate at which the work is done. It is given by :
P = W/t, W is work done and t is time
Unit of power:
Unit of work is Joule (J) and that of time is second (s). It means that the unit of power is Watt and it is equal to Joule/second
Hence, the correct option is (d) "The unit for work is a joule. The unit for power is a watt, which is a joule per second".
Answer:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
Formula: g = GM/r2
Dimensional Formula: M0L1T-2
Values of g in SI: 9.806 ms-2
Explanation:
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