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alekssr [168]
3 years ago
14

What evidence supported the Oscillating Big Bang?

Physics
1 answer:
stira [4]3 years ago
5 0
<h2>Answer with Explanation </h2>

The Oscillating Universe Theory is a cosmological model that consolidates both the Big Bang and the Big Crunch as a major aspect of a repeating occasion. That is, in the event that this hypothesis remains constant, the Universe in which we live in exists between a Big Bang and a Big Crunch.

As such, our universe can be the first of a conceivable arrangement of universes or it tends to be the nth universe in the arrangement.

As we probably are aware, in the Big Bang Theory, the Universe is accepted to extend from a hot, exceptionally thick, and little element. Actually, on the off chance that we extrapolate back to the snapshot of the Big Bang, we can achieve a point of peculiarity described by unendingly high vitality and thickness, just as zero volume.

This portrayal would just mean a certain something every one of the laws of material science will be tossed out of the window. This is naturally unsuitable to physicists. To exacerbate the situation, a few cosmologists even trust that the Universe will, in the end, achieve the greatest purpose of development and that once this occurs, it will at that point crumple into itself.

This will basically prompt indistinguishable conditions from when we extrapolate back to the snapshot of the Big Bang. To cure this difficulty, a few researchers are suggesting that maybe the Universe won't achieve the purpose of peculiarity all things considered.

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The pulley system below uses a gasoline engine to raise a drill head up through a smooth drill pipe. The engine provides a const
polet [3.4K]

NB: The diagram of the pulley system is not shown but the information provided is sufficient to answer the question

Answer:

Power = 2702.56 W

Explanation:

Let the power consumed be P

Energy expended = E = mgh

height, h = 5 m

E = 80 * 9.8 * 5

E = 3920 J

Power = \frac{Energy}{time}

To calculate the time, t

From F = ma

F = 900 N

900 = 80 a

a = 900/80

a = 11.25 m/s²

From the equation of motion, s = ut + 0.5at^{2}

The drill head starts from rest, u = 0 m/s

5 = 0 * t + (0.5*11.25*t^{2} )\\5 = 5.625t^{2}\\t^{2} = 5/5.625\\t^{2} = 0.889\\t = 0.943 s

Power, P = E/t

P = 3920/0.0.943

P = 4157.79 W

But Efficiency, E = 0.65

P = 0.65 * 4157.79

Power = 2702.56 W

6 0
3 years ago
What is the primary determinant of the voltage developed by a battery?
Fittoniya [83]
For the answer to the question above asking what is the primary determinant of the voltage developed by a battery?the answer is that the <span>the nature of the materials in the reaction that is the primary determinant of the voltage from a battery.</span>
5 0
3 years ago
Uma massa de 500 Kg desloca-se com velocidade 58 km por hora. Calcule o módulo de sua quantidade por movimento
Simora [160]

The momentum of the object is 8050 kg m/s

Explanation:

The momentum of an object is defined as

p=mv

where

p is the momentum

m is the mass

v is the velocity of the object

For the object in this problem, we have

m = 500 kg is its mass

v = 58 km/h is its velocity

Converting the velocity into m/s,

v=58 \frac{km}{h}\cdot \frac{1000 m/km}{3600 s/h}=16.1 m/s

Therefore now we can find the momentum of the object:

p=(500)(16.1)=8050 kg m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
Can someone answer all of the questions?
Katyanochek1 [597]

Answer: -200

Explanation: is it math

8 0
2 years ago
Read 2 more answers
A proton moving at 8.9 × 106 m/s through a magnetic field of 0.96 T experiences a magnetic force of magnitude 3.8 × 10−13 N. Wha
goblinko [34]

Answer: 15.66 °

Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:

F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.

From this expression and using the given values we obtain the following:

F/(q*v*B) = sin α

3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27

then  α =15.66°

8 0
3 years ago
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