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lukranit [14]
3 years ago
9

Jane is collecting data for a ball rolling down a hill. she measure out a set of different distances and then proceeds to use a

stopwatch to find the time it takes the ball to roll each distance
Physics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

<em>The Independent variable in this experiment is the time taken by the ball to roll down each distance.</em>

<em>The dependent variable is the distance  through which the ball rolls</em>

<em>The control variables are: slope of hill, weight, of the ball, size of ball, wind speed, surface characteristics of the ball.</em>

Explanation:

The complete question is

Jane is collecting data for a ball rolling down a hill. She measures out a set of different distances and then proceeds to use a stop watch to find the time it takes the ball to roll. What are the independent, dependent, and control variables in this experiment?

Independent variable have their values not dependent on any other variable in the scope of the experiment. The time for the ball to roll down the hill is not dependent on any other variable in the experiment. Naturally, <em>some common independent variables are time, space, density, mass, fluid flow rate.</em>

A dependent variable has its value dependent on the independent variable in the experiment. The value of the distance the ball rolls depends on the time it takes to roll down the hill.

The relationship between the dependent and independent variables in an experiment is given as

y = f(x)

where y is the output or the dependent variable,

and x is the independent variable.

Control variables are those variable that if not held constant could greatly affect the results of an experiment. For an experiment to be more accurate, control variables should be confined to a given set of value throughout the experiment.

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Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
4 years ago
A baseball has a mass of 0.145 kg. A professional pitcher throws a baseball 67 mi/h, which is 30.0 m/s. What is the magnitude of
Kamila [148]

The concept of momentum tells us that it is equivalent to the product between the mass and the velocity of the object, that is to say that in general it can be written as

p = mv

Where,

m = mass

v = Velocity

Our values are given as,

m = 0.145kg

v = 67mi/h = 30m/s

Replacing we have that,

p = (0.145)(30)

p = 12.45 kg\cdot m/s

Therefore the magniude of the momentum of the pitched baseball is 12.45 kg\cdot m/s

6 0
3 years ago
Read 2 more answers
Give examples of friction being useful and not useful in everyday life
Aloiza [94]
If you are cold and you rub your hands together then that friction can create warmth. Useful

If you're sliding down a staircase railing and your hands are on the raiking then the friction may burn your hands a little. Not useful<span />
6 0
3 years ago
Read 2 more answers
a particle that has a mass of 2.5 kg is moving in the positive X-direction with a constant velocity of 1.6m/s. Suddenly a consta
malfutka [58]
The particle has a constant horizontal velocity, and a vertical force won't affect the horizontal speed, so it should be fairly easy to find the last part, "the time taken for a 10m horizontal displacement," using a kinematic equation.
X = x + vt + (1/2)at²
10 = 0 + (1.6)t + (1/2)(0)t²
10/1.6 = t
t = 6.25s

So now we have to find the vertical displacement over 6.25 seconds on a particle of a 2.5kg mass with a force of 8N.
Start with Newton's second law.
F = ma
8 = (2.5)a
a = 3.2m/s²

Now, use kinematics again.
Y = y + vt + (1/2)at²
Y = 0 + (0)(6.25) + (1/2)(3.2)(6.25)²
Y = <u>62.5m</u>
7 0
3 years ago
Two identical loudspeakers are driven in phase by the same amplifier. The speakers are positioned a distance of 3.2 m apart. A p
serg [7]

Answer:

f = 735 Hz

Explanation:

given,

Person distance from speakers

r₁ = 4.1 m      r₂ = 4.8 m

Path difference

d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m

For destructive interference

d = \dfrac{n\lambda}{2}

where, n = 1, 3,5..

we know, λ = v/f

d = \dfrac{n v}{2f}

v is the speed of the sound = 343 m/s

f is the frequency

f = \dfrac{n v}{2d}

for n = 1

f = \dfrac{343}{2\times 0.7}

     f = 245 Hz

for n = 3

f = \dfrac{3\times 343}{2\times 0.7}

     f = 735 Hz

Hence,the second lowest frequency of the destructive interference is 735 Hz.

7 0
4 years ago
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