Question

At their closest approach, Venus and Earth are 4.20 × 10 10 m apart. The mass of Venus is 4.87 × 10 24 kg, the mass of Earth is 5.97 × 10 24 kg, and What is the force exerted by Venus on Earth at that point?

Answer 1

Answer:

$1.10\cdot 10^{18}N$

Explanation:

The magnitude of the gravitational force between two objects is given by :

$F=G\frac{m_1 m_2}{r^2}$

where :

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem:

$r=4.20\cdot 10^{10}m$ is the distance between Venus and the Earth

$m_1=4.87\cdot 10^{24} kg$ is Venus mass

$m_2=5.97\cdot 10^{24} kg$ is the Earth's mass

Substituting, we find the gravitational force between the two planets:

$F=(6.67\cdot 10^{-11})\frac{(4.87\cdot 10^{24})(5.97\cdot 10^{24})}{(4.20\cdot 10^{10})^2}=1.10\cdot 10^{18}N$