Question

What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal to 0.25 and the maximum voltage of the AC source is 8 V?

Answer 1

Answer:

0.08 w

Explanation:

AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.

the expression for the average power is given as

P=$V_r$$I_r$ cosΦ

We have given maximum voltage =8 volt

$V_r$=$\frac{8}{1.414}$

power factor =.25

resistance =25Ω

power factor =$\frac{R}{Z}$

power factor=$\frac{25}{Z}$

From here Z=100

P=$\frac{8}{1.414}$ ×$\frac{v_r}{Z}$ ×cosΦ

=5.6577×0.05677×0.25

=0.08w