What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal
1 answer:
Answer:
0.08 w
Explanation:
AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.
the expression for the average power is given as
P= cosΦ
We have given maximum voltage =8 volt
=
power factor =.25
resistance =25Ω
power factor =
power factor=
From here Z=100
P= ×
×cosΦ
=5.6577×0.05677×0.25
=0.08w
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Answer:
The magnitude of the second charge is or
Explanation:
The work done in bringing a charged particle from one point to another in the presence of some electric field is equal to the change in the electric potential energy of the charge in moving from one point to another.
The electric potential energy of some charge at a point in the electric field of another charge
is given by the product of the amount of charge
and electric potential at that point due to the charge
.
The electric potential at that point is given by
where is the Coulomb's constant.
Therefore,
Now, We have given two charges and
, whose value is to be found.
When the two charges are infinitely dar apart, the electric potential energy of the system is given by
When the coordinates of position of the two charges are
The distance between the two charges is given by
The electric potential energy of the charges in this configuration is given by
The change in the electric potential energy of the system is equal to the work done to bring the system from inifinitely far apart position to given configuration.
Therefore,