What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal
1 answer:
Answer:
0.08 w
Explanation:
AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.
the expression for the average power is given as
P= cosΦ
We have given maximum voltage =8 volt
=
power factor =.25
resistance =25Ω
power factor =
power factor=
From here Z=100
P= ×
×cosΦ
=5.6577×0.05677×0.25
=0.08w
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The answer to this question is: it depends. It depends on the arrangement of the capacitors in a circuit: it can be either in series or in parallel. The difference is shown in the picture.
Capacitors are like batteries in a way that they store power from the source. It has some rules depending on the type of circuit. For parallel circuits, the voltage across each capacitor is equal. Therefore, V₁=V₂=V₃.
On the other hand, if the capacitors are arranged in series, the voltage across each capacitor should add up to the total voltage of the source. Therefore, V₁+V₂+V₃ = Total Voltage.
Capacitors are like batteries in a way that they store power from the source. It has some rules depending on the type of circuit. For parallel circuits, the voltage across each capacitor is equal. Therefore, V₁=V₂=V₃.
On the other hand, if the capacitors are arranged in series, the voltage across each capacitor should add up to the total voltage of the source. Therefore, V₁+V₂+V₃ = Total Voltage.