What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal
1 answer:
Answer:
0.08 w
Explanation:
AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.
the expression for the average power is given as
P= cosΦ
We have given maximum voltage =8 volt
=
power factor =.25
resistance =25Ω
power factor =
power factor=
From here Z=100
P= ×
×cosΦ
=5.6577×0.05677×0.25
=0.08w
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Explanation:
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F - f = ma but of course it's much more involved than that simple equation! We have the F value as 230 N, and we have the mass as 105, but we do not have the frictional force, f, and we need it to solve for a in the above equation. We know that
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230 - 25 = 105a. We have to do the subtraction first, round, and then divide since the rules for addition and subtraction are different from the rules for dividing and multiplying.
230 - 25 will round to the tens place giving us 210. Then
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