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Firlakuza [10]
2 years ago
13

Question 6 of 10

Physics
1 answer:
noname [10]2 years ago
8 0

Answer:

Explanation:

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DUE TODAY PLEASE HELP.....WILL GIVE BRANIST!!!!!!!
Karo-lina-s [1.5K]

girl how someone supposed to help you with that?!

7 0
2 years ago
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A small plane flies 37.0 km in a direction 45° north of east and then flies 28.0 km in a direction 25° north of east.
Karo-lina-s [1.5K]

Answer:

d= 64.1 km θ = 36.4º

Explanation:

a) In order to find the plane's straight-line distance from the starting point, we need to know the coordinates of the final and initial position of the plane, so we can find the total displacement, as the difference between the final and initial position.

If we choose to put our origin at the initial point of trajectory, we have that (x₀, y₀) = (0, 0)

In order to find the position of the plane after finishing the flight, we need to find its final coordinates (x₁, y₁).

In order to get x₁, we need to add the x-coordinate after flying 45º north of east, and the Δx after  completing the flight in a direction 25º of east, that we can find applying trigonometry, as follows:

x₁ = 37.0 km * cos 45º + 28.0 km* cos 25º = 51.6 Km

Appying the same considerations for the y-coordinate, we have:

y₁ = 37.0 km * sin 45º + 28.0 km* sin 25º = 38.0 km

Now, as the initial position coincides with the origin, the distance in a straight line from this point to the origin, is just the hypotenuse of the triangle determined by the coordinates (x₁, y₁) and (0,0), as follows:

d = \sqrt{x1^{2}+y1^{2}} =\sqrt{(51.6km)^{2}+(38km)^{2}} =64.1 km

The geographic direction of the displacement vector (which coincides in magnitude with the distance we have just found), is just the angle that this distance forms with the east axis, that we can find getting the tangent of this angle as follows:

tg θ =\frac{y1}{x1} = \frac{38km}{56.1km} =0.736

⇒ θ = 36.4º North of East (counterclockwise from the east axis).

7 0
2 years ago
A wave has a period of 2s and a wavelength of 5m. What is the speed of the wave?
horrorfan [7]

Answer:

10m per Second

Explanation:

8 0
3 years ago
What's the voltage drop running through the parallel portion of the circuit?
Leni [432]
R 3/4 = (R3 * R4) / (R3 + R 4) = ( 9 * 18 ) /(9 + 18 ) = 162 / 27 = 6 Ohms
R e = R 1 + R 2 + R 3/4 + R 5 = 3 + 6 + 6 + 15 = 30 Ohms
I = U / Re = 90 V / 30 Ohms = 3 A
Finally for the voltage U 3/4 ( the parallel portion of the circuit ):
U 3/4 = 6 Ohms * 3 A = 18 V
Answer: 18 V 
4 0
3 years ago
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The field of a solenoid is most like the field of a: long, straight wire single bar magnet horseshoe magnet single pole
user100 [1]
The outside magnetic field of a solenoid is similar to that of a bar magnet even though the inside field is strong and uniform.
4 0
3 years ago
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