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Tanzania [10]
3 years ago
12

If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain u

sing Newton's second law
Physics
2 answers:
zaharov [31]3 years ago
6 0

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

Elenna [48]3 years ago
4 0

Answer:

the bike

Explanation:

it has less mass than the motorcycle so so it would have more acceleration

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Answer:

All these is caused by the repulsion force.

Explanation:

The electroscope produces a series of electric charges that produce a repulsion force when is putted in contact with a electric charged object.

As the physics law mentions, two different forces are repealed, the electrocospe is charged negatively and the object positively, causing a repulsion force that avoids that both objects touch the other.

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3 years ago
Which statement describes why ocean currents are considered convection currents?
Nataly_w [17]

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3 years ago
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TRUE OR FALSE
katen-ka-za [31]

Answer:

True

Explanation:

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3 years ago
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How much heat is needed to bring 12.0 g of water from 28.3 °C to 43.87 °C, if the specific heat capacity of water is 4.184 J/(g•
Vika [28.1K]

Answer:

Heat capacity, Q = 781.74 Joules

Explanation:

Given the following data;

Mass = 12g

Initial temperature = 28.3°C

Final temperature = 43.87°C

Specific heat capacity of water = 4.184J/g°C

To find the quantity of heat needed?

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 43.87 - 28.3

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Substituting into the equation, we have;

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Q = 781.74 Joules

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3 years ago
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