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Tom [10]
3 years ago
7

Five people buy individual insurance policies. According to the research, the probability of each of these people not filing a c

laim for at least 5 years is 2/3.
The probability that all 5 have not filed a claim after 5 years is A: 0.132 B: 0.868 C: 1 , and the probability that exactly 3 will have filed a claim after 5 years is A: 0.016 B: 0.033 C: 0.067 .
Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

The first part is .132 and the second is .033

Arlecino [84]3 years ago
3 0
P(no claim after 5 years) = (2/3)^5 =  0.132
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Consider a family that generates 20 loads of laundry in a week. based on the data in the table, what is the total number of peop
liq [111]

The total number of people in the family that generates 20 loads of laundry in a week is 10.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the number of people and x represent the number of laundry loads.

From the table:

y = (1/2)x

For 20 loads:

y = (1/2) * 20 = 10

The total number of people in the family that generates 20 loads of laundry in a week is 10.

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5 0
2 years ago
This pattern follows the rule divide by 2, then add 8. What are the next two numbers?
krok68 [10]

Answer:

32, 24

Step-by-step explanation:

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3 0
3 years ago
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
3 years ago
Need help asap pls!!!
lisabon 2012 [21]

Answer:

16

Step-by-step explanation:

According to the given description, PS is the mid segment of the \triangle TQR

Therefore by Mid-segment Theorem:

PS = \frac{1}{2}  QR \\  \\ PS = \frac{1}{2}   \times 32 \\  \\ PS =16 \:

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3 years ago
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Answer:

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Step-by-step explanation:

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