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Ostrovityanka [42]
3 years ago
11

Lye is a common ingredient in drain cleaning products. It is made of one atom of sodium, one atom of oxygen, and one atom of hyd

rogen.
Which of the following correctly represents the chemical formula for lye?

NaOH
Na 1O 1H 1
SOHe
S 1O 1H 1
Chemistry
1 answer:
il63 [147K]3 years ago
8 0
The answer would be NaOH
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What does the word distal mean?
erica [24]

There are two meanings to the word "Distal"

   Anatomy

  1.    situated away from the center of the body or from the point of attachment.

 

      Geology

    2.   relating to or denoting the outer part of an area affected by geological activity.

       

5 0
4 years ago
Which of the following is not a reason why actual yield is less than theoretical yield?
Gnom [1K]
Your answer is B, conservation of mass


Recall that percent yield is given by: %Yeild = actual yeild/theoretical yeild x100

During experiments, there are errors made:

• uncertainty in measurements

• losses of reactants and products

• impurity in reactants

• losses during separation (e.g. filtration or purification)

• Some side reactions might also happen.



Among the given options, only conservation of mass does not contribute to a lower actual yield compared to the theoretical yield.

5 0
3 years ago
Calculate the number of moles of a gas that is present in a 7.55 L container at 45°C, if the gas exerts a pressure of 725mm Hg.
vovikov84 [41]

<u>Answer:</u> The number of moles of gas present is 0.276 moles

<u>Explanation:</u>

To calculate the number of moles of gas, we use the equation given by ideal gas:

PV = nRT

where,

P = Pressure of the gas = 725 mm Hg

V = Volume of the gas = 7.55 L

n = number of moles of gas = ?

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of the gas = 45^oC=(45+273)K=318K

Putting values in above equation, we get:

725mmHg\times 7.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 318K\\\\n=0.276mol

Hence, the number of moles of gas present is 0.276 moles

4 0
3 years ago
How can objects all be the same size but have a different mass? *help quick*
Elodia [21]

Answer:

All objects can have the same size but have a different mass!

This is true, although it sounds fake. This is one example, there is a Neutron star, and Neutron stars are as big as a city, but they have a mass which is hundreds of times greater than our sun's mass. Because of them having so much mass, they are also having so much gravitational energy, which makes them also have gravity. They're so small, but have so much mass that they can do much. Even a drop of a neutron star can punch open the earth! It's true, so yes, it is possible for objects the SAME size to be having different masses according to that example.

But let's look on how they can have different mass.

They can have different masses becase of different densities. Put a iron ball inside water, and put an apple as close to the iron ball's side, what happens? The apple floats, becuase the apple's mass is less than the water, and the iron ball's mass is MORE than the water. So, because the iron ball is denser than the apple, that's why, it has more mass than the apple. The apple isn't much dense, it isn't as dense as water or the iron ball. But the iron ball is much more denser than the water. So because of the different material densities of the material, that's why it can have different masses.

Remember to Remember those 2 examples I gave you... (neutron star vs sun, iron ball vs apple on water)

8 0
2 years ago
What is the frequency of radiation whose wavelength is 2.51 x 10 -7m?​
hodyreva [135]

The frequency of radiation : 1.2 x 10¹⁵ Hz

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

<h3>f = c / λ </h3>

c = speed of light

= 3.10⁸  m/s

λ = wavelength

Wavelength-λ is 2.51 x 10⁻⁷m

The frequency :

\tt f=\dfrac{3.10^8}{2.51\times 10^{-7}}=1.2\times 10^{15}

8 0
3 years ago
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