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Naddik [55]
2 years ago
14

According to the usda food standards and labeling, vinegar must contain at least 4% (m/m) acetic acid. does your vinegar sample

meet this standard?
a) yes, our vinegar meets the usda standard.
b) no, our vinegar does not meet the usda standard.
Chemistry
1 answer:
Anastasy [175]2 years ago
7 0

Answer:

A for me

Explanation:

I dont know what you mean by this as this is an opinon question

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The claim is the farther the ball drops the higher it will bounce. What are the reasonings and evidence
lions [1.4K]

Answer:

Hey,

As the ball falls, it gains gravitational kinetic energy or GKE, all that means is that it starts to move faster as it falls, As it does so it gains more and more energy so that when it falls it will bounce realy high, it can't destribute all that energy in 1 hit, for such a task you would need a cannon ball.

<em><u>Wbob1314</u></em>

5 0
3 years ago
21) What is the volume (inL) of 3470 g of liquid glycerol, which has a density of 1.26 g/?
Illusion [34]

Answer:

V = 2.75 L

Explanation:

Given that,

Mass of liquid glycerol, m = 3470 g

The density of liquid glycerol, d = 1.26 g/cm³

We need to find the volume of liquid glycerol.

We know that,

Density=mass/volume

V=\dfrac{m}{d}\\\\V=\dfrac{3470\ g}{1.26\ g/cm^3}\\\\V=2753.96\ cm^3

We know that, 1 cm³ = 0.001 L

V = 2.75 L

So, the volume of liquid glycerol is 2.75 L.

6 0
3 years ago
Unlike solids and liquids, gases can be compressed. How is this physical characteristic of gases beneficial to society?
Anna35 [415]
Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form. An internal combustion engine provides a good example of the ease with which gases can be compressed.
6 0
3 years ago
Remember to balance the equations first
Semenov [28]

mol CO₂ = 9.6

mol N₂ = 4.8

mol O₂ = 0.8

mol H₂O = 8

<h3>Further explanation</h3>

Reaction

4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O

mol CO₂

\tt \dfrac{12}{4}\times 3.2=9.6

mol N₂

\tt \dfrac{6}{4}\times 3.2=4.8

mol O₂

\tt \dfrac{1}{4}\times 3.2=0.8

mol H₂O

\tt \dfrac{10}{4}\times 3.2=8

8 0
3 years ago
Question 14(multiple choice worth 2 points) a student had a sample of pure water, and added an unknown substance to it. the stud
pantera1 [17]
The answer is A its basic

5 0
3 years ago
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