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Gennadij [26K]
3 years ago
6

Often, waves are said to be "out of phase" with one another. This means that one wave is shifted so that the peaks and troughs a

re not simultaneous. Which type of interference could be seen as "out of phase"?
A) positive

B) negative
Physics
2 answers:
grandymaker [24]3 years ago
8 0
I believe the correct answer is “negative” ?? Not sure but I think
snow_lady [41]3 years ago
8 0

Answer: It’s Negative

Explanation: Just did it on USA test prep

When two waves come close to one another, their effects add together. ... In fact, if the two waves (with the same amplitude) are shifted by exactly half a wavelength ... The resulting combined wave will have no crests or troughs at all, and will ... That means that there will always be constructive interference at that spot, therefore its negative.

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\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

       So, in the current problem, the natural length of the spring is not required to find the spring constant k.

       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

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