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4 years ago

Gravitational force is determined by which of the following

Physics

1 answer:

hram777 [196]4 years ago

8 0

Gravitational force is determined by mass

Answer: Option B

<u>Explanation:</u>

According to Universal law of gravity, the gravitational force is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the objects.

$F=G \times \frac{m_{1} \times m_{2}}{r^{2}}$

Where,

G – gravitational constant = $\text { 6. } 67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}$

$\boldsymbol{m}_{1}, \boldsymbol{m}_{2}$ = masses of two objects

r – distance between the objects

So, as per this law, the gravitational force is found by mass.

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Un bloque de 25 n se encuentra suspendido por un hilo al techo vitamina la tensión que aparece en el hilo

SVETLANKA909090 [29]

Answer:

T = 25 N

Explanation:

The question says that "A 25 n block is suspended by a wire from the ceiling vitamin the tension that appears in the wire ?"

Weight of the block, W = 25 N

Weight of a body acts in downward direction and tension acts in upward direction. It would mean that,

Tension = weight of the block

T = mg

T = 25 N

Hence, the tension in the wire is 25 N.

7 0

3 years ago

An elements atomic number is 85 how many protons would an atom of this element have?

garik1379 [7]

85 protons are in astatine have.

5 0

3 years ago

Read 2 more answers

Blood in a carotid artery carrying blood to the head is moving at 0.15 m/s when it reaches a section where plaque has narrowed t

sp2606 [1]

Answer:

26.9 Pa

Explanation:

We can answer this question by using the continuity equation, which states that the volume flow rate of a fluid in a pipe must be constant; mathematically:

$A_1 v_1 = A_2 v_2$ (1)

where

$A_1$ is the cross-sectional area of the 1st section of the pipe

$A_2$ is the cross-sectional area of the 2nd section of the pipe

$v_1$ is the velocity of the 1st section of the pipe

$v_2$ is the velocity of the 2nd section of the pipe

In this problem we have:

$v_1=0.15 m/s$ is the velocity of blood in the 1st section

The diameter of the 2nd section is 74% of that of the 1st section, so

$d_2=0.74d_1$

The cross-sectional area is proportional to the square of the diameter, so:

$A_2=(0.74)^2 A_1=0.548 A_1$

And solving eq.(1) for v2, we find the final velocity:

$v_2=\frac{A_1 v_1}{A_2}=\frac{A_1 (0.15)}{0.548 A_1}=0.274 m/s$

Now we can use Bernoulli's equation to find the pressure drop:

$p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho v_2^2$

where

$\rho=1025 kg/m^3$ is the blood density

$p_1,p_2$ are the initial and final pressure

So the pressure drop is:

$p_1 - p_2 = \frac{1}{2}\rho (v_2^2-v_1^2)=\frac{1}{2}(1025)(0.274^2-0.15^2)=26.9 Pa$

8 0

3 years ago

How much does a 10 kg

Goshia [24]

Answer:

Explanation:

because during free fall we experience wieghtlessness

5 0

2 years ago

A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm? Check all that apply.

kherson [118]

Answer:

The answers are options B,D and E

Explanation:

B) The particles in the liquid are slowly overcoming the forces of attraction and spreading out due to the thermal energy they are absorbing. This makes the liquid less dense as it slowly changes into a gas after reaching its boiling point.

D) The particles start absorbing the energy form the surroundings as latent heat of evaporation. They need this energy to overcome the strong forces of attraction between particles to change into the gaseous state

E) The particles have spaced out due to the thermal energy absorbed, making the liquid lighter and it rises upwards.

5 0

3 years ago