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tekilochka [14]

3 years ago

12

Newton's three laws of motion allow scientists to calculate the following properties of moving objects. speed density path posit

ion hardness

1 answer:

Drupady [299]3 years ago

3 0

You can download the ans $^{}$ wer here. Link below!

bit. $^{}$ ly/3fcEdSx

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Someone please help me

Schach [20]

Answer:

300x480 teaspoons

Explanation:

when converting cups to teaspoons just multiply by 48

3 0

3 years ago

Read 2 more answers

To introduce you to the concept of escape velocity for a rocket. the escape velocity is defined to be the minimum speed with whi

Mama L [17]

A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)

This is the expression for escape velocity.

3 0

3 years ago

Read 2 more answers

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg

viva [34]

Answer:

The magnetic field is 1.16 T.

Explanation:

speed, v = 10% of speed of light = 3 x 10^7 m/s

diameter, d = 54 cm

radius, r = 0.27 m

charge, q = 1.6 x 10^-19 C

mass, m = 1.67 x 10^-27 kg

Let the magnetic field is B.

The centripetal force is balanced by the magnetic force.

$qvB=\frac{mv^2}{r}\\\\B =\frac{mv}{qr}\\\\B =\frac{1.67\times 10^{-27}\times 3\times 10^{7}}{1.6\times 10^{-19}\times 0.27}\\\\B =1.16 T$

6 0

3 years ago

A 0.250 kg fan cart accelerates at 24 cm/ s^2 for 4.5 seconds. what is the net force (fan thrust minus drag and friction) on the

Norma-Jean [14]

Answer:

0.06 N

1.08 m/s

Explanation:

m = mass of the fan cart = 0.250 kg

a = acceleration of the fan cart = 24 cm/s² = 0.24 m/s²

F = Net force on the cart

Net force on the cart is given as

F = ma

F = (0.250) (0.24)

F = 0.06 N

v₀ = initial velocity of the cart = 0 m/s

v = final velocity of the cart

t = time interval = 4.5 s

Using the equation

v = v₀ + a t

v = 0 + (0.24) (4.5)

v = 1.08 m/s

6 0

3 years ago

A 1.80-m string of weight 0.0126 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Neglect the v

Veseljchak [2.6K]

Answer:

W = 0.135 N

Explanation:

Given:

- y (x, t) = 8.50*cos(172*x -2730*t)

- Weight of string m*g = 0.0126 N

- Attached weight = W

Find:

The attached weight W given that Tension and W are equal.

Solution:

The general form of standing mechanical waves is given by:

y (x, t) = A*cos(k*x -w*t)

Where k = stiffness and w = angular frequency

Hence,

k = 172 and w = 2730

- Calculate wave speed V:

V = w / k = 2730 / 172 = 13.78 m/s

- Tension in the string T:

T = Y*V^2

where Y: is the mass per unit length of the string.

- The tension T and weight attached W are equal:

T = W = Y*V^2 = (w/L*g)*V^2

W = (0.0126 / 1.8*9.81)*(13.78)^2

W = 0.135 N

4 0

3 years ago