54.5 mL of liquid gallium metal is poured into a graduated cylinder. The gallium filling the graduated cylinder weighs 10.686 g.
1 answer:
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<u>Answer:</u> The temperature of the system is 273 K
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of carbon dioxide = 1 lb = 453.6 g (Conversion factor: 1 lb = 453.6 g)
Molar mass of carbon dioxide = 44 g/mol
Putting values in above equation, we get:
To calculate the temperature of gas, we use the equation given by ideal gas equation:
PV = nRT
where,
P = Pressure of carbon dioxide = 200 psia = 13.6 atm (Conversion factor: 1 psia = 0.068 atm)
V = Volume of carbon dioxide = (Conversion factor:
)
n = number of moles of carbon dioxide = 10.31 mol
R = Gas constant =
T = temperature of the system = ?
Putting values in above equation, we get:
Hence, the temperature of the system is 273 K
Answer:
C) 0.800 mol
Explanation:
- 4Al + 3O₂ → 2Al₂O₃
In order to <u>convert from moles of Al₂O₃ into moles of Al</u>, we'll need to use<em> the stoichiometric coefficients</em>, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:
- 0.400 mol Al₂O₃ *
= 0.800 mol Al
So the correct answer is option C).