Answer:
В. No, because the mass of the reactants is less than the mass of the products.
Explanation:
Chemical equation:
NaBr + Cl₂ → 2NaCl + Br₂
The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.
There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.
Balanced chemical equation:
2NaBr + Cl₂ → 2NaCl + Br₂
Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.
The activation energy is the minimum required energy in order to start a reaction. It is the barrier to break to enable reactants to form products. It is not important only for some reactions but to all reactions. This energy should be supplied or reached first before we observe a reaction to happen.
The equilibrium constant of the reaction is 0.042.
The reaction equation is given as;
PCl5(g) ⇄ PCl3(g) + Cl2 (g)
Recall that this equation shows the decomposition of phosphorus pentachloride.
We have the following equilibrium concentrations;
[PCI5]= 0.0095 M
[PCI3] = 0.020
[CI2] = 0.020 M
The equilibrium constant, K is obtained from;
K = [PCI3] [CI2]/[PCI5]
K = [0.020]^2/[0.0095]
K = 0.042
Learn more: brainly.com/question/17960050
Maybe for solid u could do just standing still, for liquid you could do waving ur arms by ur side, and for gases you can wave your arms and legs around. I did the same thing last yr and that’s what I wrote, gl
this is so ez,
ok so here what u'll do after u balance the equation:
1. convert grams of oxygen to moles of oxygen.
2. convert moles of oxygen to moles of water
3. convert moles of water to grams of water.
4. bOOm... that's your answer
as follows:
2H2O(l)===>2H2(g)+O2(g)
1. 151200(g)/16(g/mol)=9540 moles of O2
2. 9450 moles of O2 × 2 moles of H2O =18900 moles of H2O
3. 18900 moles of H2O × 10g/mol = 189000g of H2O is required.
