Answer: The range of wavelengths of light that can be used to cause given phenomenon is
.
Explanation:
Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J
Formula used is as follows.
![E = \frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where,
E = energy
h = Planck's constant = ![6.625 \times 10^{-25} Js](https://tex.z-dn.net/?f=6.625%20%5Ctimes%2010%5E%7B-25%7D%20Js)
c = speed of light = ![3 \times 10^{8} m/s](https://tex.z-dn.net/?f=3%20%5Ctimes%2010%5E%7B8%7D%20m%2Fs)
Substitute the values into above formula as follows.
![E = \frac{hc}{\lambda}\\222000 J = \frac{6.625 \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D%5C%5C222000%20J%20%3D%20%5Cfrac%7B6.625%20%20%5Ctimes%2010%5E%7B-34%7DJs%20%5Ctimes%203%20%5Ctimes%2010%5E%7B8%7D%20m%2Fs%7D%7B%5Clambda%7D%5C%5C%5Clambda%20%3D%208.953%20%5Ctimes%2010%5E%7B21%7D%20m)
Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is
.
Answer: Neutron matter is equivalent to a chemical element with atomic number 0, which is to say that it is equivalent to a species of atoms having no protons in their atomic nuclei. Neutron matter decays quickly into hydrogen. Neutron matter has no electronic structure on account of its total lack of electrons.
Explanation:
Answer:
Molecular weight of the compound = 372.13 g/mol
Explanation:
Depression in freezing point is related with molality of the solution as:
![\Delta T_f = K_f \times m](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%20K_f%20%5Ctimes%20m)
Where,
= Depression in freezing point
= Molal depression constant
m = Molality
![\Delta T_f = K_f \times m](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%20K_f%20%5Ctimes%20m)
![1.33 = 5.12 \times m](https://tex.z-dn.net/?f=1.33%20%3D%205.12%20%5Ctimes%20m)
m = 0.26
Molality = ![\frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}](https://tex.z-dn.net/?f=%5Cfrac%7BMoles%5C%20of%5C%20solute%7D%7BMass%5C%20of%5C%20solvent%5C%20in%5C%20kg%7D)
Mass of solvent (toluene) = 15.0 g = 0.015 kg
![0.26 = \frac{Mole\ of\ compound}{0.015}](https://tex.z-dn.net/?f=0.26%20%3D%20%5Cfrac%7BMole%5C%20of%5C%20compound%7D%7B0.015%7D)
Moles of compound = 0.015 × 0.26 = 0.00389 mol
![Mol = \frac{Mass\ in\ g}{Molecular\ weight}](https://tex.z-dn.net/?f=Mol%20%3D%20%5Cfrac%7BMass%5C%20in%5C%20g%7D%7BMolecular%5C%20weight%7D)
Mass of the compound = 1.450 g
![Molecular\ weight = \frac{Mass\ in\ g}{Moles}](https://tex.z-dn.net/?f=Molecular%5C%20weight%20%3D%20%5Cfrac%7BMass%5C%20in%5C%20g%7D%7BMoles%7D)
Molecular weight = ![\frac{1.450}{0.00389} = 372.13\ g/mol](https://tex.z-dn.net/?f=%5Cfrac%7B1.450%7D%7B0.00389%7D%20%3D%20372.13%5C%20g%2Fmol)
Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .
- That's the best explanation i can give IF ITS NOT ENUH OR NOT RIGHT JUH COMMENT BELOWW↓↓ I WILL THINK OF SOMEThING ELSE THANKS! YOU HAVE A GREAT DAYY .
Answer:
c. reversible favoring products, equilibrium constants are calculated in an equation of the type aA + bB = cC + dD, were Keq = ([C][D]) / ([A][B]).
Explanation:
If the equilibrium constant is just greater than 1, that means that the products are favored.