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mrs_skeptik [129]
2 years ago
15

What part of the leaf is responsible for absorbing the sun’s energy?

Chemistry
1 answer:
never [62]2 years ago
3 0

Answer:chlorophyll

Explanation:

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How are parentheses used in chemical formulas
Liula [17]
They make the symbols individual
6 0
3 years ago
A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.
zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

 For group 2 member, let the metal  = X;

 The carbonate is XCO₃;

 If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

 Atomic mass of C = 12g/mol

                            O  = 16g/mol

 Atomic mass of X + 12 + 3(16)  = 84

  Atomic mass of X  = 84 - 60  = 24g/mol

The element with atomic mass of 24g is Magnesium

B.

Number of moles in 0.3g of CaCO₃:

     Molar mass of CaCO₃   = 40 + 12 + 3(16)  = 100g/mol

 Number of moles = \frac{mass}{molar mass}  

 Number of moles  = \frac{0.3}{100}   = 0.003mole

7 0
3 years ago
Which part of the crust is the thickest
Sergio039 [100]

Answer:

I'll take a gander at your question

Explanation:

If you mean the Earth's crust, your answer is The Mantle.

5 0
3 years ago
In a particular redox reaction, no2– is oxidized to no3– and cu2 is reduced to cu . Complete and balance the equation for this r
lianna [129]

Reduction half reaction: Cu²⁺(aq) + 2e⁻ → Cu⁰(s).


Oxidation half reaction: NO₂⁻(aq) + H₂O(l) → NO₃⁻(aq) + 2H⁺(aq) + 2e⁻.  

Balanced chemical reaction:

Cu²⁺(aq) + NO₂⁻(aq) + H₂O(l) → Cu(s) + NO₃⁻(aq) + 2H⁺(aq).

Copper is reduced from oxidation number +2 (Cu²⁺) to oxidation number 0 (Cu) and nitrogen is oxidized from oxidation number +3 (in NO₂⁻) to oxidation number +5 (in NO₃⁻).


8 0
3 years ago
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Chemistry question! Please help!
Illusion [34]

When a solid (solute) comes in contact with the liquid (solvent), the solute goes about C) dissolution, in which the solid dissolves into the liquid.

~

7 0
3 years ago
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