A 1500 kg car traveling east at 40 km/hr turns a corner and speeds up to a velocity of 50 km/hr due north. What is the change in
1 answer:
Answer:
96046 Ns.
Explanation:
We shall represent velocity in vector form considering east direction as + ve x axis and north as + y direction.
40 km/h in the east
V₁ = 40 i
V₂ = 50j
momentum p₁ = mV₁
= 1500 X 40 i
= 60000 i
Momentum p₂ = mV₂
= 1500 X 50j
= 75000 j
Change in momentum
p₂ - p₁
75000j - 60000i
Magnitude of change
=
= 96046 Ns.
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Answer:
a. 3.039cm
b.magnetic field is
Explanation:
Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:
Angle of net magnetic field from axial direction is given by:
,
Field due to solenoid:
Field due to wire:
Therefore, r:
Hence, the radial distance is 3.039cm
b.The magnetic field strength is given by:
Hence, the magnetic field is
Answer:
404.4 m
Explanation:
Converting the initial speed from km/h to m/s then
The acceleration is resolved as shown in the figure hence
deceleration of the truck along the inclined plane will be
where g is acceleration due to gravity
Substituting g with then
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and making s the subject then
where v and u are final and initial velocities respectively
Substituting 0 for v, 38.89 m/s for u and then
