Gradient of the line is m =-2/5
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Answer:
D(t) = 8(0.83)^(t) cos 38πt
Explanation:
We are told that the spring oscillates 19 times each second.
Thus, period = 1/19
We are also told that it's pulled 8cm downwards and the amplitude decreases by 17% each second.
Thus;
Amplitude;A = 8 × (1 - (17/100))^(t)
A = 8(0.83)^(t)
If we consider the function;
y = A cos (bx - c) + d
Now, 2π/b = period
So, 1/19 = 2π/b
b = 38π
So, D(t) = 8(0.83)^(t) cos (38πt - c) + d
Since we started from minimum,
Vertical shift, d = 0 and horizontal shift c = 0
So,we now have;
D(t) = 8(0.83)^(t) cos 38πt
The initial momentum of the car is
(mass) x (speed) = 20,000 kg-m/s
"Impulse" is (force exerted) x (time the force lasts)
and it's equal to the change in momentum.
(Force) x (10 sec) = 20,000 kg-m/s
Divide each side by (10 sec) and you have
Force = (20,000 kg-m/s) / (10 sec)
= 2,000 kg-m/s² = 2,000 Newtons