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mixer [17]
3 years ago
5

Bonnie and Clyde are sliding a 323 kg bank safe across the floor to their getaway car. The safe slides with a constant speed if

Clyde pushes from behind with 383 N of force while Bonnie pulls forward on a rope with 343 N of force. What is the coefficient of friction between the safe and the floor?
Physics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

835/(320*9.8)=0.266

Explanation:

since the safe is moving at a constant speed then the net force is zero

in other words the friction force equals the sum of Bonnie and Clyde force

so the friction force must be 485+350=835N

the frictional force = mu*m*g

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The intensity of most of the cyclonic storm reduces after hitting land. Explain giving suitable reasons.
yulyashka [42]

The intensity of most cyclones reduces after hitting land because land takes away the heat and moisture of tropical ocean water. In order to survive, cyclone storms need evaporation from the warm sea surface. Intensity also decreases because of greater fiction on land, compared to the sea surface.

5 0
3 years ago
Read 2 more answers
How can I answer question 19? please help me, I need the answer now
Crank
The spring starts out 22 cm long with nothing hanging on it.

Hanging 35 newtons of weight on it stretches the spring 1 meter.

Ellen is going to hang 250 grams of mass on the spring.
What's the weight of 250 grams of mass ?

   Weight = (mass) x (acceleration of gravity in the place where the mass is) .

On Earth, the acceleration of gravity is 9.8 m/s² .
250 grams is 0.25 of a kilogram.

Weight of 250 grams  =  (0.25 kilogram) x (9.8 m/s²)

                                 =    (0.25 x 9.8)  kg-m/s²

                                 =        2.45 newtons .

2.45 newtons of weight is  (2.45 / 35) of 35 newtons,
so it'll stretch the spring  (2.45 / 35) of a meter.

   2.45/35 = 0.07 of a meter  =  7 centimeters.

The spring was 22 cm long with nothing hanging on it,
and the 250-gm weight stretched it 7 cm.
So with the weight hanging on it, it's (22 + 7) = 29 cm long.

6 0
3 years ago
The diffusion constant for oxygen diffusing through tissue is 1.0 × 10-11 m2/s. In a certain sample oxygen flows through the tis
Eduardwww [97]

Answer:

m' = 1 x 10⁻⁶ kg/s

Explanation:

Given that

Diffussion constant = 1 x 10⁻¹¹

Mass flow rate ,m = 2 x 10⁻⁶ kg/s

The diffusion is inversely proportional to the thickness of the membrane and therefore when the thickness is doubled, the mass flow rate would become half.

So new flow rate m'

m'=\dfrac{m}{2}

m'=\dfrac{2\times 10^{-6}}{2}\ kg/s

m' = 1 x 10⁻⁶ kg/s

6 0
3 years ago
Liquid water can be separated into hydrogen gas and oxygen gas through electrolysis. 1 mole of hydrogen gas and 0.5 moles of
den301095 [7]

The temperature of the oxygen gas is  243.75 K.

Using ideal gas law to explain the answer, the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure of the gas increases.

The reaction of the given elements;

H_2 \ + \ \frac{1}{2} O_2 \ --->\ \ H_2O

volume of the collected oxygen gas, V = 10 L

pressure of the gas, P = 1 atm

number of moles of the gas, n = 0.5

Using ideal law the temperature of the oxygen gas is calculated as follows;

PV = nRT\\\\T = \frac{PV}{nR} \\\\where;\\R \ is \ the \ ideal \ gas \ constant = 0.08205 \ L.atm/K.mol\\\\T = \frac{1 \times 10 }{0.5 \times 0.08205} \\\\T = 243.75 \ K

Thus, the temperature of the gas is 243.75 K.

Using ideal gas law to explain the answer. The absolute temperature of the oxygen gas is directly proportional to the product of its pressure and volume and inversely proportional to its number of moles. That is the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure increases.

Learn more here: brainly.com/question/16617695

8 0
3 years ago
If an open pipe of length vibrates in fundamental mode, then pressure variation is maximum
KIM [24]

Answer:

(B) at the middle of the pipe

Explanation:

In the case of an open pipe which vibrates in fundamental mode, an anti-node is formed at the middle of the pipe, here the amplitude of the wave is maximum. Hence, the pressure variation is also maximum at the middle.

8 0
3 years ago
Read 2 more answers
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