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Llana [10]
3 years ago
14

Neutron stars are:

Physics
2 answers:
SpyIntel [72]3 years ago
7 0

C). I think! Hope this helps!!


True [87]3 years ago
4 0
C) This is because: A neutron star is the collapsed core of a giant star which before collapse had a total of between 10 and 29 solar masses. A neutron star has a mass of about 1.4 times the mass of the sun.
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When Stone B collides with Stone A during Test 2, Stone B stops and Stone A begins to move. Which statement BEST describes the m
Anna11 [10]

Answer:

A

Explanation:

According to law of conservation of momentum, the total momentual in the system will be conserved

5 0
2 years ago
What force accelerates a 500 kg object at 5 m/s2?
Alexxx [7]

Answer:

2500N

Explanation:

f = m.a

m=500 kg

a=5 m/s²

f = 5*500 kgm/s² = 2500 N

7 0
3 years ago
Read 2 more answers
7 One lb of Refrigerant 134a contained within a piston–cylinder assembly undergoes a process from a state where the temperature
julsineya [31]

Answer:

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb ^ {\circ} R}

Explanation:

A) In order to solve the table it is necessary to consult tables A11-E and A10E for refrigerant R134-a

In this way we obtain that:

S_1 = S_f = 0.0648 \frac {BTU} {Lb. ^ {\circ} R}

In this way,

S_2 = S_f + x_2 (S_g-S_f) = 0.0902 + 0.5 (0.2161-0.0902)

S_2 = 0.15315 \frac {BTU} {Lb ^ {\circ} R}

In this way the entropy change is,

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb. ^ {\°} R}

B) Whenever entropy yields a positive result, the process can be carried out adiabatically.

7 0
3 years ago
The magnetic circuit below is excited by a 100-turn coil wound over the central leg. The mean length of the central leg is 5.5cm
Dafna11 [192]

Answer:

Hello your question is incomplete attached below is the complete question and solution

<em>answer; </em>

attached below

Explanation:

<em>Given data:</em>

100-turn coil

mean length of central leg = 5.5 cm

mean length of outer paths = 15.5 cm

relative permeability = 2000

cross sectional area ( A ) = 1 cm^2

distance x = 1 cm  

attached below is a detailed solution

3 0
2 years ago
What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
Sauron [17]

The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

<h3>What is a frequency?</h3>

The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.

Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,

\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma  = 6.88 \times 10^{14}\ s^{-1}

Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

Learn more about Frequency:

brainly.com/question/5102661

#SPJ4

5 0
2 years ago
Read 2 more answers
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