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Alja [10]
3 years ago
15

A 9.13e+3 kg railroad car is rolling at 3.15 m/s when a 4.20e+3 kg load of gravel is suddenly dropped in from directly above. Wh

at is the car's speed immediately after the gravel is dropped in?
Physics
1 answer:
Feliz [49]3 years ago
6 0

Answer:

6.85 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum.

In fact, since there are no external forces acting, the total momentum before and after must be conserved. So we can write:

m_1 v_1 = m_2 v_2

where

m_1 = 9.13\cdot 10^3 kg is the initial mass of the car

v_1 = 3.15 m/s is the initial speed of the car

m_2 = 9.13\cdot 10^3 kg - 4.20\cdot 10^3 kg=4.93\cdot 10^3 kg is the mass of the car after the load of gravel is dropped

v2 is the final speed of the car

Solving for v2, we find

v_2 = \frac{m_1 v_1}{m_2}=\frac{(9.13\cdot 10^3)(3.15 m/s)}{4.93\cdot 10^3}=6.85 m/s

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Answer:

t = 3.0s

Explanation:

U = 2.0m/s , V = 0 (stop) , S = 3m , t =?

From V^2 - U^2 = 2aS

=) a = -4/6 = -0.667m/s^2

Now again by V-U = at

We have t = -U/a = 2/0.667 = 3s

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6 0
3 years ago
Consider two less-than-desirable options. In the first you are driving 30 mph and crash head-on into an identical car also going
4vir4ik [10]

Answer:

B. The force would be the same in both cases.

Explanation:

According to Newton's 3rd law where impulse was equated to the momentum formula.

F × t = M × V

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Force = F

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Since, Impulse is force multiplied by time, whereas the time of contact is the same for both, therefore the impulse is the same in magnitude for the two trucks.

Case 1: Hitting the other car

Case 2: Hitting the brick wall

In Case 1, both the cars are identical and have same velocity whereas in the Case 2, the wall is stationary.

The case of hitting the brick wall have the same impact force as hitting the other car, because they have the same change in momentum.

Therefore, The force would be the same in both cases.

6 0
4 years ago
I need help with this please
34kurt
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The National Aeronautics and Space Administration (NASA) studies the physiological effects of large accelerations on astronauts.
m_a_m_a [10]

Answer:

v = 23.95 m/s

Explanation:

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here we know that

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Answer D. Inertial mass constant, weight decreases.

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