The pressure at the bottom of the tank is given by:
P = ρgh
P = pressure, ρ = fluid density, g = gravitational acceleration, h = depth
Given values:
ρ = 820kg/m³, g = 9.8m/s², h = 4.5m
Plug in and solve for P:
P = 820(9.8)(4.5)
P = 36000Pa
Wind and water is the answer
Hope this helps!
Answer:
contains many young stars
Explanation:
Irregular galaxies have <em>no definite shape</em>, which means that the first option is incorrect. They are definitely not round.
However,<u> they contain many young stars because the degree of star formation is fast.</u> They also contain old stars. Thus, the second choice is correct.
The "spiral galaxy" is the type of galaxy that has arms that extend from the center. These arms look "spiral," which influenced its name. This makes the last choice incorrect.
They are actually <u>smaller than the other types of galaxies.</u> This makes them <em>prone to collisions</em>. This makes the last choice incorrect.
Answer:
The truce ended all wars
Explanation:
The Olympic Truce or the sacred truce, is the declaration made by ambassadors for the laying down of arms and the stop of all hostilities starting from seven days before the Olympic games began and ending seven days after the games to provide safe passage for travelling athletes and also spectators to and from the Olympic games
However, the games were held during Persian wars and also during the Peloponnesian wars. As such the truce stopped mainly conflicts that have direct impact on the Olympic games and there was an attack in Olympia in 364 BC during the games.
the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.
Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(
l
M
)dx The moment of inertia of small piece about the YY' axis
dl=[(
l
M
)dx]x
2
Therefore, the moment of inertia of the complete rod about the YY' axis.
b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I
CD
is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;
l
CD
=l
YY
′
+Md
2
=
12
Ml
2
+M(
2
l
)
2
l
CD
=
3
Ml
2
.........(2)
