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miss Akunina [59]
2 years ago
5

A car with bad shock absorbers bounces up and down with a period of 1.50 s after hitting a bump. The car has a mass of 1 500 kg

and is supported by four springs of equal force constant k. Determine the value of k.
Physics
1 answer:
kkurt [141]2 years ago
6 0

Answer:

k =  26319 N/m

Explanation:

given,

Period of bounce = 1.5 s

mass of the car = 1500 kg

four springs                    

to find the value of k                              

T = 2\pi \sqrt{\dfrac{m}{k}}      

1.5 = 2\pi \sqrt{\dfrac{1500}{k}}

\dfrac{2.25}{4\pi^2}=\dfrac{1500}{k}      

k = \dfrac{4\pi^2 \times 1500}{2.25}      

k =  26319 N/m            

Now the value of force constant is k =  26319 N/m      

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Now, on substituting the values and plugging it into the equation, we have

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Sound travels around 340 m/s the function d(t =340 gives the distance d(t in meters that sound travels in t seconds how far does
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7 0
3 years ago
3
Misha Larkins [42]

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

KE = \frac{1}{2}mv^2

KE = Kinetic Energy (J)
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v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

U_s = \frac{1}{2}kx^2

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2

We can simplify and solve for 'x'.

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Plug in the givens and solve.

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