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miss Akunina [59]
3 years ago
5

A car with bad shock absorbers bounces up and down with a period of 1.50 s after hitting a bump. The car has a mass of 1 500 kg

and is supported by four springs of equal force constant k. Determine the value of k.
Physics
1 answer:
kkurt [141]3 years ago
6 0

Answer:

k =  26319 N/m

Explanation:

given,

Period of bounce = 1.5 s

mass of the car = 1500 kg

four springs                    

to find the value of k                              

T = 2\pi \sqrt{\dfrac{m}{k}}      

1.5 = 2\pi \sqrt{\dfrac{1500}{k}}

\dfrac{2.25}{4\pi^2}=\dfrac{1500}{k}      

k = \dfrac{4\pi^2 \times 1500}{2.25}      

k =  26319 N/m            

Now the value of force constant is k =  26319 N/m      

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A 49 N coconut is in a 15 m tree. What is te potential energy of the coconut?
eduard

Answer:

735 J

Explanation:

From the question given above, the following data were obtained:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:

Potential energy = weight × height

With the above formula, we can obtain the potential energy of the coconut as follow:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy = weight × height

Potential energy = 49 × 15

Potential energy = 735 J

Thus, the potential energy of the coconut is 735 J

4 0
3 years ago
Two disks of polaroid are aligned so that they polarize light in the same plane. Calculate the angle through which one sheet nee
Olegator [25]

Answer: The unpolarized light's intensity is reduced by the factor of two when it passes through the polaroid and becomes linearly polarized in the plane of the Polaroid. When the polarized light passes through the polaroid with the plane of polarization at an angle \theta with respect to the polarization plane of the incoming light, the light's intensity is reduced by the factor of \cos^2\theta (this is the Law of Malus).

Explanation: Let us say we have a beam of unpolarized light of intensity I_0 that passes through two parallel Polaroid discs with the angle of \theta between their planes of polarization. We are asked to find \theta such that the intensity of the outgoing beam is I_2. To solve this we follow the steps below:

Step 1. It is known that when the unpolarized light passes through a polaroid its intensity is reduced by the factor of two, meaning that the intensity of the beam passing through the first polaroid is

I_1=\frac{I_0}{2}.

This beam also becomes polarized in the plane of the first polaroid.

Step 2. Now the polarized beam hits the surface of the second polaroid whose polarization plane is at an angle \theta with respect to the plane of the polarization of the beam. After passing through the polaroid, the beam remains polarized but in the plane of the second polaroid and its intensity is reduced, according to the Law of Malus, by the factor of \cos^2\theta. This yields I_2=I_1\cos^2\theta. Substituting from the previous step we get

I_2=\frac{I_0}{2}\cos^2\theta

yielding

\frac{2I_2}{I_0}=\cos^2\theta

and finally,

\theta=\arccos\sqrt{\frac{2I_2}{I_0}}

3 0
3 years ago
9) A bug of mass 0.020 kg is at rest on the edge of a solid cylindrical disk (M = 0.10 kg, R = 0.10 m) rotating in a horizontal
natima [27]

Answer:

a. ω₂ = 14rad/s

b. ∇K.E = 0.014J

c. The bug does not conserve force while moving on the disk (non-conservative force).

Explanation:

Mass of the bug (m) = 0.02kg

Mass of the cylindrical disk (M) = 0.10kg

Radius of the disk (r) = 0.10m

Initial angular velocity ω₁ = 10rad/s

final angular velocity ω₂ = ?

a.

To calculate the new angular velocity, we relate it to the conservation of angular momentum of the system I.e when the bug was at the edge of the disk and when it is located at the centre of the disk.

I = Mr² / 2

I₁ = Mr₂ / 2 + mr²

I₁ = moment of inertia when the bug was at the edge

I₁ = [(0.10 * 0.10²) / 2 ] + (0.02 * 0.1²)

I₁ = 0.0005 + 0.0002

I₁ = 7.0*10⁻⁴kgm²

I₂ = moment of inertia when yhe bug was at the center of the disk.

I₂ = Mr² / 2

I₂ = (0.01 * 0.01²) 2

I₂ = 0.0005kgm²

for conservation of angular momentum,

I₁ω₁ = I₂ω₂

solve for ω₂

ω₂ = (I₁ * ω₁) / I₂

ω₂ = (7.0*10⁻⁴ * 10) / 5.0*10⁻⁴

ω₂ = 14 rad/s

b. the change in kinetic energy of the system is

∇K = K₂ - K₁

∇K = ½I₂*ω₂² - ½I₁*ω₁²

∇K = ½(I₂*ω₂² - I₁ω₁²)

∇K = ½[(5.0*10⁻⁴ * 14²) - (7.0*10⁻⁴ * 10²)]

∇k = ½(0.098 - 0.07)

∇K = ½ * 0.028

∇K = 0.014J

c.

The cause of the decrease and increase in kinetic energy is because the bug uses a non-conservative force. To conserve the mechanical energy of a system, all the forces acting in it must be conservative.

The work W produced by this force brings the difference in kinetic energy of the system

W = K₂ - K₁

6 0
3 years ago
ANSWER ASAP
Galina-37 [17]

Answer:

I'm not great at science, but I believe that the answer is elastic potential energy.

Explanation:

Components of mechanical systems store elastic potential energy if they are deformed when forces are applied to the system. Energy is transferred to an object by work when an external force displaces or deforms the object.

6 0
3 years ago
You are driving down the road and hit a bump which causes your fishing tackle
valina [46]
Answer:
speed
=
12

m/s

Explanation:
We're asked to find the initial velocity of the box, given it constantly accelerated at
−
3

m/s
2
for
24

m
before coming to a stop.
To do this, we can use the equation
(
v
x
)
2
=
(
v
0
x
)
2
+
2
a
x
(
Δ
x
)
−−−−−−−−−−−−−−−−−−−−−−
where
v
x
is the final velocity of the box (which is
0
since it came to rest)

v
0
x
is the initial velocity of the box (what we're trying to find)

a
x
is the acceleration of the box, given as
−
3

m/s
2
(negative because it's directed opposite to motion; i.e. it is decelerating)

Δ
x
is the distance traveled by the box, given as
24

m


Plugging in knonw values, we have
0
=
(
v
0
x
)
2
+
2
(
−
3
l
m/s
2
)
(
24
l
m
)

v
0
x
=
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣


12
l
m/s

∣
∣
−−−−−−−−−−−−
The truck was thus traveling at a speed of
12

m/s
.
8 0
4 years ago
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