Answer:
the boat would be deeped by 3200 m
Explanation:
Given that
The boat arrives back after 4 seconds
And, the speed of the sound in water is 1,600 m/s
We need to find out how much deep is the water
So,
As we know that
Distance = ( speed × time) ÷ 2
Here we divided by 2 because the boat arrives back
= (1600 × 4) ÷ 2
= 3200 m
Therefore the boat would be deeped by 3200 m
Answer: Load divided by it effort
Explanation:
Mechanical advantage of any machine is its load divided by its effort
Answer:
94.1 m
Explanation:
From Coulombs law,
F = Gm1m2/r²................... Equation 1
where F = force, m1 = first mass, m2 = second mass, G = universal constant, r = distance of separation.
Make r the subject of the equation,
r = √(Gm1m2/F)................. Equation 2
Given: F = 7×10² N, m1 = 15×10⁷ kg, m2 = 62×10⁷ kg,
Constant: G = 6.67×10⁻¹¹ Nm²/kg²
Substitute into equation 2
r = √( 6.67×10⁻¹¹×15×10⁷×62×10⁷/7×10²)
r √(886.16×10)
r √(88.616×10²)
r = 9.41×10
r = 94.1 m.
Hence the distance of separation = 94.1 m
Answer:
Explanation:
We are given that
The wavelength of sound wave=
1 cm/s=
Speed of sound wave,v=
We have to find the period of the wave.
We know that
Frequency=
Using the formula
Frequency =
Hz
Time period=
Using identity:
Hence, the time period of the wave=
Answer:
40,000
Explanation:
Momentum is defined as mass*velocity, so a doubling of velocity means a doubling of momentum
