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ohaa [14]
1 year ago
8

A particle is moving in a circle of diameter 5. calculate the distance covered and the displacement when it completes 3 revoluti

ons.
Physics
1 answer:
Mamont248 [21]1 year ago
5 0

Total distance covered is 47.1 m whereas displacement is zero.

<h3>Calculation:</h3>

Given,

Diameter, d = 5 m

No. of revolutions = 3

Radius, r = 5/2 = 2.5 m

To find,

Distance =?

Displacement =?

Distance covered in one revolution = 2πr

                                                           

Put the values in this,

Distance = 2 × 3.14 × 2.5

               = 15.7 m

Total distance covered in 3 revolution = 3 × 31.4

                                                                = 47.1 m

Displacement is the change in the position of the object or the distance between the initial and final position.

After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.

Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.

Learn more about distance and displacement here:

brainly.com/question/3243551

#SPJ4

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What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE ar
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Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

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From the question, we got that the mass of the planet is

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M = 9 * 5.95*10^24

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Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

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On applying the values of both R and M to the equation, we get

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Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

Please vote brainliest if it helped you <3

5 0
3 years ago
Please help me I’ll mark brainless .
Ivan
The mass is 10.811 hope this helps
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Answer: Your code returns a number of 99.123456789 +0.00455679

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But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.

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LOL! couldnt be me either bestieeeee

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