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Butoxors [25]
3 years ago
10

I need help with this ASAP!!!

Physics
1 answer:
yarga [219]3 years ago
5 0
Just look up the words that are given and see the definition lol
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You have a resistor of resistance 200 ? and a 6.00-?F capacitor. Suppose you take the resistor and capacitor and make a series c
Ne4ueva [31]

Answer:

eazy

Explanation:

hi bro it is very hard so I can't help and I don't the answer

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4 years ago
the volume of ice block is 2400cm^3 and its density is 0.9 g/cm^3. how much part of it remains above the surface of water when i
stiks02 [169]

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

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V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

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3 years ago
What is the meaning of friend ?​
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6 0
3 years ago
The distance between two objects is increased by 3 times the original distance. How will this change he force of attraction betw
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3 0
3 years ago
A transverse wave is set up in a very long string. The oscillator is set at 20.0 Hz, and the wave speed is 78 m/s. The amplitude
Sedbober [7]

To solve this problem we must apply the concepts related to Tangential Acceleration based on angular velocity and acceleration, and therefore, we must also calculate angular velocity based on the given frequency. For all these problems we will take the Units to the International System. The maximum acceleration would then be defined as,

a_{max} = \omega^2 A

Here,

\omega= Angular velocity

A = Amplitude

At the same time the angular velocity is described as,

\omega = 2\pi f

Here f means the frequency of the wave. Substituting,

\omega = 2 \pi (20)

\omega = 40\pi

A = 5.2cm

A = 0.052m

Replacing at the first equation,

a_{max} = (40\pi )^2 (0.052)

a_{max} = 821.15m/s^2

Therefore the maximum particle acceleration for a point on the string is 821.15m/s^2

6 0
4 years ago
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