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Harlamova29_29 [7]
3 years ago
10

Describe how the number of photoelectrons emitted from a metal plate in the photoelectric effect would change if the following o

ccurred.(a) the intensity of the incident radiation were increasedAs long as the radiation has a frequency above the cutoff value, the greater the intensity the larger the flux of photoelectrons that flow off of the metal plate. If the frequency of the light is below the cutoff, it does not matter how much the intensity is increased. No photoelectrons will be emitted.As long as the radiation has a frequency above the cutoff value, the greater the intensity the lower the flux of photoelectrons that flow off of the metal plate. If the frequency of the light is below the cutoff, it does not matter how much the intensity is increased. No photoelectrons will be emitted.As long as the radiation has a frequency below the cutoff value, the greater the intensity the larger the flux of photoelectrons that flow off of the metal plate. If the frequency of the light is above the cutoff, it does not matter how much the intensity is increased. No photoelectrons will be emitted.none of these(b) the wavelength of the incident radiation were increasedIf the wavelength is increased, the energy of the radiation will decrease. If it slips above the work function of the metal plate, the photoelectric effect will cease.none of theseIf the wavelength is increased, the energy of the radiation will decrease. If it slips below the work function of the metal plate, the photoelectric effect will cease.If the wavelength is increased, the energy of the radiation will increase.If it slips below the work function of the metal plate, the photoelectric effect will cease.(c) the work function of the metal were increasedIf the work function of the metal is increased, it will eventually grow past the energy of the incident photons and the effect will intensify.The flux of photoelectrons that flow off of the metal plate will decrease gradually as the work function is increased.There will be no change in the effect if the work function of the metal is increased.If the work function of the metal is increased, it will eventually grow past the energy of the incident photons and the effect will cease
Physics
1 answer:
andrew-mc [135]3 years ago
7 0

Answer:

a) True. The number of photoelectrons is proportional to the amount (intensity) of the incident beam. From the expression above we see that threshold frequency cannot emit electrons.

b)   λ = c / f

Therefore, as the wavelength increases, the frequency decreases and therefore the energy of the photoelectrons emitted,

c)  threshold energy

        h f =Ф

Explanation:

It's photoelectric effect was fully explained by Einstein by the expression

       Knox = h f - fi

Where K is the kinetic energy of the photoelectrons, f the frequency of the incident radiation and fi the work function of the metal

a) True. The number of photoelectrons is proportional to the amount (intensity) of the incident beam. From the expression above we see that threshold frequency cannot emit electrons.

b) wavelength is related to frequency

         λ = c / f

Therefore, as the wavelength increases, the frequency decreases and therefore the energy of the photoelectrons emitted, so there is a wavelength from which electrons cannot be removed from the metal.

c) As the work increases, more frequency radiation is needed to remove the electrons, because there is a threshold energy

        h f =Ф

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An atom with the expected number of neutrons, protons, and electrons is called a(n)
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Stable atom

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Power selection feature for resistors to become water modules 10 liters of water at 25°C to đến
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Answer:

P = 2439.5 W = 2.439 KW

Explanation:

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Mass = (Density)(Volume)

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Now, we will find the energy required to heat the water between given temperature limits:

E = mCΔT

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Therefore,

E = (10 kg)(4182 J/kg.°C)(70°C)

E = 2.927 x 10⁶ J

Now, the power required will be:

Power = P = \frac{E}{t}

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Therefore,

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3 years ago
The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m
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Answer:

0.0360531138247 V/m

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The  electric field in the wire is 0.0360531138247 V/m

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4 years ago
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